All categories

2 years ago

In a reaction of an acid with a base, the pH changes to a value that is closer to what?

1 answer:

8 0

The pH changes to a value closer to 7, which is considered neutral.

This, however, only applies to all reactions between strong acids and strong bases. If the reaction either involves a weak acid and/or a weak base, the computation of the final pH may slightly be more complicated.

You might be interested in

How many moles of copper (Cu) are in 65.8 g Cu?

Veseljchak [2.6K]

<h2><u>Answer:</u></h2>

The correct answer is A) 1.04 mol Cu

{65.8 g / 63.55 g/mol}

= 1.04 mol Cu

Explanation:

In 63.55 g of copper metal there are 1 m o l of C u atoms. By dividing the mass of Cu and molar mass, we can easily get the number of moles.

5 0

3 years ago

Read 2 more answers

Who wants to make some Chemistry????... UwU

Alik [6]

Answer:

what kind of chemistry is it going to be?

8 0

2 years ago

Read 2 more answers

Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac

GalinKa [24]

<h2>a) The rate at which $NO_2$ is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen $O_2$ is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of $NO$ = $-\frac{1d[NO]}{2dt}$ = 0.066 M/s

Rate in terms of disappearance of $O_2$ = $-\frac{1d[O_2]}{dt}$

Rate in terms of appearance of $NO_2$ = $\frac{1d[NO_2]}{2dt}$

1. The rate of formation of $NO_2$

$-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}$

$\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s$

2. The rate of disappearance of $O_2$

$-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}$

$-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s$

Learn more about rate law

brainly.com/question/13019661

https://brainly.in/question/1297322

7 0

3 years ago

Please help ASAP! PLEASE DO NOT GIVE ME A RANDOM GIBBERISH ANSWER OR ELSE I WILL REPORT YOU AND GIVE YOU A LOW RATING!!!

UNO [17]

Answer:

if an object weighs more than an equal volume of water, it is more dense and will sink, and if it weighs less than an equal volume of water, it is less dense and will float.

Explanation:

Hope that helps

8 0

2 years ago

Why do atoms gain or lose electrons?

Aleksandr [31]

Answer:kapil

Explanation:

Atoms lose electrons, if an electron gets more energy than then binding energy of the electron. This may be because of a collision with a charged particle or because of absorbtion of a photon. In a metal, there are just other positive charges nearby. The electron is not lost, but shared.

6 0

3 years ago