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Yuri [45]
2 years ago
11

Which feature of a balanced chemical equation demonstrates the law of

Chemistry
2 answers:
Scrat [10]2 years ago
8 0

Answer:

Option D

Explanation:

it has the same types of atoms on both sides of the reaction

JulijaS [17]2 years ago
4 0

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D) It has the same types of atoms on both sides of the reaction arrow.

Explanation:

This law was made by the Antoine Lavoisier in 1789. He want to confirm that the mass of reactant is equal to the mass of product and he was successful to carry out the test.

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Answer:

What is the question?

Explanation:

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What are the signs that you are getting nervous 18 POINTS )
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- hands start getting sweaty
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3 years ago
What volume of chlorine gas measured at StP will be liberated by a current of 2.5 A flowing for a period of 1.8 hours through an
Oliga [24]

The volume of chlorine gas measured at STP will be liberated by a current of 2.5  A flowing for a period of 1.8 hours through an aqueous solution of AgCl is 1.88 litre.

<h3>What is Faraday's law ?</h3>

According to Faraday's Law , During Electrolysis , The amount of substance liberated at the cathode or anode is directly proportional to the electricity that is passed through the cell.

The reaction taking place at anode is:

2Cl → Cl₂ +2e −

The total charge is calculated as

Q=I×t= 2.5×1.8×60×60 coulomb

Q = 16200 coulomb

The amount of chlorine liberated by passing 16200 coulomb of electric charge

= 16200/(2*96500)

= 0.084 mole

Volume of Cl₂ at STP is

​1 mole at STP has 22.4 L of Gas

0.084 mole of Cl₂ at STP will be equal to 22.4 *0.084 = 1.88 litre of Cl₂

To know more about Faraday's Law

brainly.com/question/1640558

#SPJ1

3 0
2 years ago
Na2S2O3 + AgBr NaBr + Na3ſAg(S203)2] What is
gtnhenbr [62]

Answer:

Mass of NaBr produced  = 23.67 g

Explanation:

Given data:

Mass of AgBr = 42.7 g

Mass of NaBr produced = ?

Solution:

Chemical equation:

2Na₂S₂O₃ + AgBr    →    NaBr + Na₃(Ag(S₂O₃)₂

Number of moles of AgBr:

Number of moles = mass/molar mass

Number of moles = 42.7 g/ 187.7 g/mol

Number of moles = 0.23 mol

now we will compare the moles of AgBr with NaBr.

             AgBr        :         NaBr

                1            :           1

              0.23       :         0.23

Mass of NaBr:

Mass = number of moles × molar mass

Mass = 0.23 mol × 102.89 g/mol

Mass = 23.67 g

8 0
3 years ago
Can anyone help me please
Sergio039 [100]
The answer is 159.69 g/mol
6 0
3 years ago
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