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Yuri [45]
2 years ago
11

Which feature of a balanced chemical equation demonstrates the law of

Chemistry
2 answers:
Scrat [10]2 years ago
8 0

Answer:

Option D

Explanation:

it has the same types of atoms on both sides of the reaction

JulijaS [17]2 years ago
4 0

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D) It has the same types of atoms on both sides of the reaction arrow.

Explanation:

This law was made by the Antoine Lavoisier in 1789. He want to confirm that the mass of reactant is equal to the mass of product and he was successful to carry out the test.

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What is the molar mass of fluorine, F2?
Naily [24]
<span>37.9968064 ± 0.0000010 g/mol</span>
8 0
3 years ago
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Use this condensed chemical structure
liberstina [14]

Answer:

number of carbon-carbon single (C - C) bonds: 1

number of carbon-hydrogen single (C H) bonds: 5

number of nitrogen-hydrogen sing le (N H) bonds:2

number of lone pairs: 1

Explanation:

Ethanamine is a colourless gas having a strong 'ammonia- like' odour. It contains the -NH2 group which makes it an amine. It contains one carbon-carbon bond, five carbon-hydrogen bonds and two nitrogen-hydrogen bonds.

Nitrogen, being sp3 hybridized in the compound has a lone pair of electrons localized on one of the sp3 hybridized orbitals of nitrogen while one sp3 hybridized orbital of nitrogen is used to form a carbon-nitrogen bond. The other two sp3 hybridized orbitals on nitrogen are used to form the two nitrogen-hydrogen bonds.

6 0
3 years ago
______ molecules have no net electrical charge
Reptile [31]

Answer:

A nonpolar molecule has no separation of charge

Explanation:

4 0
3 years ago
he heat of fusion of tetrahydrofuran is . Calculate the change in entropy when of tetrahydrofuran melts at . Be sure your answer
lana [24]

Answer:

\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Explanation:

Hello.

In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

\Delta S=\frac{n*\Delta H}{T}

Whereas n accounts for the moles which are computed below:

n=5.9g*\frac{1mol}{72g} =0.082mol

Thus, the entropy turns out:

\Delta S=\frac{0.0819mol*8.5 kJ/mol}{(-108.5+273.15)K}\\\\\Delta S=1.8x10^{-3}\frac{kJ}{K}=1.8\frac{J}{K}

Best regards.

3 0
3 years ago
Are these correct? Thank you!! If they are not, which do I fix?
Gennadij [26K]
This looks correct to me! <3 have a good day
3 0
3 years ago
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