Answer:
3 moles of CaO
Explanation:
The chemical balanced equation is;
2Ca + O₂ → 2CaO
The ratio of calcium(Ca) to Calcium Oxide(Cao) in this equation is 2:2.
Now, when 3 moles of calcium react with oxygen, Cao produced will be;
3 moles of O₂ × 2 moles of CaO/2 moles of Cao = 3 moles of CaO
Answer:
it depends on the assignment but im down
Explanation:
Answer:
267.14 iron oxide.
Explanation:
Given that
We know that molecular mass of iron-oxide = 160 g/mole.
We know that molecular mass of iron = 56 g/mole.
From the above reaction we can say that
1 mole of iron -oxide produce 2 mole of iron
160 gm of iron oxide produce 112 gm of iron
So
1 gm of iron required of iron oxide
Therefore
187 gm of iron required of iron oxide.
Therefore 187 gm of iron required 267.14 iron oxide.
Answer:
Each magnet should have been tested on many different magnetizable materials
Explanation:
In designing an experiment such as that outlined above, the experimental design should have included many different magnetizable materials.
All the types of magnets; the horseshoe, the bar, and the ring magnet should have been tested using many different magnetizable materials apart from the metal object. By so doing, the strongest magnet can be effectively determined without bias because it will attract the greatest number of magnetizable materials.
Again, the shape of the magnet affects its ability to attract objects. Hence, different shapes of magnets can not effectively be compared for relative magnetic strength.
Through mass spectrometry, we can define 4 different isotopes of the BrCl molecule:
⁸¹Br³⁷Cl, ⁸¹Br³⁵Cl, ⁷⁹Br³⁷Cl, ⁷⁹Br³⁵Cl
Masses of the different individual isotopes:
³⁷Cl=36.966
³⁵Cl=34.968
⁸¹Br=80.916
⁷⁹Br=78.918
Masses of 4 different isotopes of the BrCl molecule:
⁸¹Br³⁷Cl=80.916+36.966=117.882
⁸¹Br³⁵Cl=80.916+34.968=115.884
⁷⁹Br³⁷Cl=78.918+36.966=115.884
⁷⁹Br³⁵Cl=78.918+34.968=113.886