Answer:
B
Step-by-step explanation:
The correct formula given is:
![Ax+By=c](https://tex.z-dn.net/?f=Ax%2BBy%3Dc)
We need to solve for y. First, we isolate the "y" term:
![Ax+By=c\\By=c-Ax](https://tex.z-dn.net/?f=Ax%2BBy%3Dc%5C%5CBy%3Dc-Ax)
Now, there's a "B" with y, to isolate the "y", we need to divide both sides by "B" and get "y":
![By=c-Ax\\\frac{By}{B}=\frac{c-Ax}{B}\\y=\frac{c-Ax}{B}](https://tex.z-dn.net/?f=By%3Dc-Ax%5C%5C%5Cfrac%7BBy%7D%7BB%7D%3D%5Cfrac%7Bc-Ax%7D%7BB%7D%5C%5Cy%3D%5Cfrac%7Bc-Ax%7D%7BB%7D)
Answer choice B is right.
Answer:
There is one solution: 2
Step-by-step explanation:
We need to distribute the 2 to (5x-8) which gets us the equation:
4 + 10x - 16 = 2x + 4
Add like terms on the left side
10x - 12 = 2x +4
Get the variable "x" to one side and isolate it
8x = 16
Divide both sides by 8
x = 2
2 is the only solution to this problem
When you square +6 or -6 you get 36. That's less than 40.
When you square +7 or -7, you get 49. That's more than 40.
So one of the square roots of 40 is between <em>+6 and +7</em>, and
the other square root of 40 is between <em>-7 and -6 </em>.
Answer:
The maximun height that the rocket will reach is 3150 ft.
Step-by-step explanation:
This problem requieres that we maximize the function. For this we need the function to be of the form:
![f(x)=ax^2+bx+c](https://tex.z-dn.net/?f=f%28x%29%3Dax%5E2%2Bbx%2Bc)
We already have that covered, as the height of the rocket is represented by:
![h(t)=-14t^2+420t](https://tex.z-dn.net/?f=h%28t%29%3D-14t%5E2%2B420t)
We start calculating the derivative of h(t), wich is:
![h'(t)=-28t+420](https://tex.z-dn.net/?f=h%27%28t%29%3D-28t%2B420)
We need to remember that the derivative of a function represents the slope of said function at a given point. The maximum value of the function will have a slope equal to zero.
So we find the value in wich the derivative equals zero:
![0=-28t+420\\28t=420\\t=\frac{420}{28}\\t=15](https://tex.z-dn.net/?f=0%3D-28t%2B420%5C%5C28t%3D420%5C%5Ct%3D%5Cfrac%7B420%7D%7B28%7D%5C%5Ct%3D15)
This means that 15 seconds is the time at wich the rocket will reach it's maximum height.
We replace this value in the original equation to solve the problem:
![h(15)=(-14)(15^2)+(420)(15)\\h(15)=-3150+6300\\h(15)=3150](https://tex.z-dn.net/?f=h%2815%29%3D%28-14%29%2815%5E2%29%2B%28420%29%2815%29%5C%5Ch%2815%29%3D-3150%2B6300%5C%5Ch%2815%29%3D3150)
With this we can conclude that the maximum height the rocket will reach is 3150 ft.
Answer:
y=2.999973
Step-by-step explanation:
Let's solve your equation step-by-step.
Step 1: Simplify both sides of the equation.
Step 2: Subtract y from both sides.
Step 3: Divide both sides by 0.125001.
y=2.999973