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Maksim231197 [3]
3 years ago
10

X2+2x +2 is equivalent to.

Mathematics
2 answers:
kompoz [17]3 years ago
5 0

Answer:

=1

Step-by-step explanation:

charle [14.2K]3 years ago
4 0
////// The answer is: 4x+2
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When calculating accrued interest over several years that compounds annually, you must calculate a new principle each year, adding the accrued interest from the previous year. At the beginning of the new interest period, all the accrued interest is added to the principal which forms a new principle figure that the interest is then counted on. 
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Mark is playing soccer. He is
eimsori [14]

Answer:

it would be 3 yards because it went 2° to the right

7 0
3 years ago
PLZ ans have mocks plz
Yanka [14]

Answer:

The table will be:

x |-2 | -1 | 0 | 1 | 2  

y | 1  | 4 | 5 | 4 | 2

Step-by-step explanation:

The function is:

y=5-x^{2}

a) The x values of the table is:

x |-2 | -1 | 0 | 1 | 2

So, when x = -2, y will be:

y(-2)=5-(-2)^{2}=5-4=1

Doing the same with the other x values we have:

y(-1)=5-(-1)^{2}=5-1=4

y(0)=5-(0)^{2}=5

y(1)=5-(1)^{2}=5-1=4

y(2)=5-(2)^{2}=5-4=1

The table will be:

x |-2 | -1 | 0 | 1 | 2  

y | 1  | 4 | 5 | 4 | 1

I hope it helps you!

5 0
3 years ago
Which is the following represents the general term for the sequence 1,3,5,7,9
irinina [24]
N+2 is the answer because you add 2 to the previous term to get the next one.
6 0
3 years ago
#2: Solve the linear system below using the elimination method. Type your
MariettaO [177]

The given linear system is:

\displaystyle \left \{ {{5x+7y=33} \atop {11x+7y=39}} \right.

The question is asking to solve using elimination. When eliminating, you can either eliminate x or y. In this system, y is much easier to eliminate. The y variable in both equations are 7y. To eliminate, one of them has to be negative, so multiply one of the equations by -1.

I will be multiplying the second equation by -1.

\displaystyle (11x + 7y = 39) \times -1 = -11x-7y=-39

Rewrite the system:

\displaystyle \left \{ {{5x+7y=33} \atop {-11x-7y=-39}} \right.

Subtract:

5x+7y=33\\-11x-7y=-39

5x-11x=33-39\\-6x=-6

Lastly, you need to leave the variable x alone. The variable is currently -6x or -6 times x. To remove it, you need to do the opposite of it, which is dividing by -6.

\displaystyle \frac{-6x}{-6} =\frac{-6}{-6}

\displaystyle x=1

Now that you have the value of x, substitute it into one of the equations to find y. I will be substituting it into the first equation.

5x+7y=33 \rightarrow 5(1)+7y=33

Open the parentheses and multiply:

5+7y=33

Move 5 to the other side to leave the variable alone:

5+7y-5=33-5

You will be subtracting since you're "removing" it by doing the opposite of it.

7y=28

Lastly, divide both sides by 7 to leave y alone.

\displaystyle \frac{7y}{7} =\frac{28}{7}

y=4

\displaystyle (x,y) \rightarrow (1, 4)

The answer is (1, 4).

8 0
2 years ago
Read 2 more answers
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