A process with a negative change in enthalpy and a negative change in entropy will generally be: <u>spontaneous</u>.
<h3>Gibbs free energy:</h3>
Since the Gibbs free energy is a parameter that tells us whether a chemical reaction is spontaneous (Gibbs free energy less than 0) or nonspontaneous (Gibbs free energy greater than 0) in this situation, we can describe it mathematically as:
ΔG = ΔH - TΔS
Therefore, any process with a negative change in enthalpy and a positive change in entropy will be spontaneous. If the enthalpy and the entropy are both negative, the subtraction becomes always negative, for which the Gibbs free energy is also negative.
One of the most crucial thermodynamic functions for the characterization of a system is the Gibbs free energy. It influences results like the voltage of an electrochemical cell and the equilibrium constant for a reversible reaction, among others.
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Answer:
100.11 m
Explanation:
Given:
Coefficient of volume expansion,
/°C.
Initial length of rod, 
Change in temperature, ΔT=
°C
We know that,
/°C
Here,
is the coefficient of linear expansion.
Now, we know that,
Change in length (Δl) is given as,

Plug in all the values and solve for
.
This gives,
Therefore, the length of rod after expansion is
m.
As we know that in transformers we have

here we know that



now from above equation we will have



Answer:
0.78m (rounded to nearest hundredth of a meter)
explanation:
time taken for going up=time taken for drop down after reaching the highest point. at the highest point, the velocity becomes 0.
now all thats left is dropping an object from a height (h) and seeing how long it takes to reach the ground. then find out the flight’s total time divided by 2 (0.8/2=0.4)
lets say the velocity is v and the height she jumped to is h. we can make a kinematic expression:
s=vt+½gt²
once we put it all together you should get this:
h=0×0.4+½(9.81) 0.4²
.
∴
Time taken for downward drop
=
0.8
2
=
0.4
s
Suppose that she jumped with initial velocity
=
u
Also suppose that she jumped to a height
h
Using following kinematic expression
s
=
u
t
+
1
2
g
t
2
and inserting various quantities we get
h
=
0
×
0.4
+
1
2
(
9.81
)
0.4
2
h
=
0.78
m
rounded to nearest hundredth of a meter.