Answer:
The magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
Explanation:
The total linear acceleration is the vector sum of the tangential acceleration and radial acceleration.
The radial acceleration is given by;
where;
a is the angular acceleration and
r is the radius of the circular path
Determine time of the rotation;
Determine angular velocity
ω = at
ω = 1.6 x 0.707
ω = 1.131 rad/s
Now, determine the radial acceleration
The magnitude of total linear acceleration is given by;
Therefore, the magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
Answer:
d = 185.26 meters
Explanation:
It is given that,
Launching angle of the projectile, 
Initial speed of the projectile, u = 48 m/s
Let at distance d the projectile hits the ground from the launch point. It is equal to range of the projectile. Its formula is given by :
Substituting all the values in above formula. So, we get :
d = 185.26 meters
So, the distance between the launch point and the point where it hits is 185.26 meters. Hence, this is the required solution.
False, because I doesn’t matter if there is noise pollution the child will still able to learn the way words work
Answer:
A
Explanation:
1. When the block moves across a table top, F(pulling) = - F(frictional).
Sum of this forces = 0, so the block moves with uniform speed.
2. When the block is pulled on top of the table covered with beads
F(pulling) > - F(frictional).
So, the sum of forces (∑F) is a number that is more than 0 and directed to the direction of movement.
So, a = ∑F / m is positive and constant. Speed is increasing because
v(t) = v(0)+at
a is constant and directed forward.
That means a is acceleration, and constant.
Answer:
a) -5.40 rad/s
b) -2.842 rad/s²
Explanation:
The direction is important in dealing with such questions. Clockwise is considered negative and counterclockwise is considered positive
a) Δω = final angular velocity - initial angular velocity
= -2.70 rad/s - 2.70 rad/s
= -5.40 rad/s
b) ∝ = Δω/Δt = (-5.40 rad/s)/1.90s = -2.842 rad/s²
