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3 years ago

After a meal.

Physics

1 answer:

Tema [17]3 years ago

6 0

Answer:

1-3hours

Explanation:

This is because a diabetic patients have increased blood sugar or glucose concentration. After eating a meal, the blood glucose concentration will be increased as it is been accumulated . Therefore it is best diabetic patient exercise at that hour to reduce it's blood glucose concentration.

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8. During the last few kilometers of a marathon, runners play mental games to test each

o-na [289]

Answer:

The runner's average acceleration is 0.102 m/s²

Explanation:

The runner accelerates from 5 m/s to 5.2 m/s and covering 10 m

We need to find the runner's average acceleration

The given is:

→ Initial velocity 5 m/s

→ Final velocity 5.2 m/s

→ Distance 10 meters

→ Acceleration ?

We need a suitable rule for the given

→ v² = u² + 2 a s

where v is the final velocity, u is the initial velocity, a is the acceleration

and s is the distance

Substitute the values above in the rule

→ (5.2)² = (5)² + 2 a (10)

→ 27.04 = 25 + 20 a

Subtract 25 from both sides

→2.04 = 20 a

Divide both sides by 20

→ a = 0.102 m/s²

<em>The runner's average acceleration is 0.102 m/s²</em>

3 0

3 years ago

The battery is made up of three 1.5 V cells.

IrinaVladis [17]

Answer: 4.5 V

Explanation:

Given

The voltage of each cell is 1.5 V

If they are connected end to end their potential added to give a higher potential i.e. 1.5+1.5+1.5=4.5 V

6 0

3 years ago

The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.0 cm apart with a 20 kV potential

Julli [10]

Answer:

A) electric field strength between the plates;E = 2 x 10^(6) N/C

B) exit velocity;v = 8.39 x 10^(7) m/s

Explanation:

We are given;

Potential difference; V = 20 kV = 20000 V

Distance between the 2 parallel plates; d = 1cm = 0.01 m

A) The electric field strength will be gotten from;

E = V/d

E = 20000/0.01

E = 2000000

E = 2 x 10^(6) N/C

B) For exit speed, we'll use the formula for Kinetic energy; KE = (1/2)mv²

KE is also expressed as; V•q_e

Thus,

(1/2)mv² = V•q_e

Where;

V is potential difference = 20000 V

Q_e is charge of electron which has a constant value of; (1.6 x 10^(-19))C

m is mass of electron with a constant value of (9.1 x 10^(-31)) kg

v is the velocity

Thus, making v the subject, we have;

v = √((2V•q_e)/m)

v = √((2 x 20000•(1.6 x 10^(-19)))/(9.1 x 10^(-31)))

v = 83862786 m/s or

v = 8.39 x 10^(7) m/s

3 0

3 years ago

Water flows at 0.850 m/s from a hot water heater, through a 450-kPa pressure regulator. The pressure in the pipe supplying an up

grin007 [14]

Answer:

The velocity is $v_2= 0.45 \ m/s$

Explanation:

From the question we are told that

The initial speed of the hot water is $v_1 = 0.85 \ m/s$

The pressure from the heater $P_1 = 450 \ KPa = 450 *10^{3} \ Pa$

The height of the hot water before flowing is $h_1 = 0 \ m$

The height of bathtub above the heater is $h_2 = 3.70 \ m$

The pressure in the pipe is $P_2 = 414 KPa = 414 *10^{3} \ Pa$

The density of water is $\rho = 1000 \ kg/m^3$

Apply Bernoulli equation

$P_1 + \rho gh_1 +\frac{1}{2} \rho v_1^2 = \rho g h_2 + \frac{1}{2}\rho v_2 ^2$

Substituting values

$(450 *10^{3}) + (1000 * 9.8 * 0) + (0.5 * 1000 * 0.85^2) = (1000 * *9.8*3.70) + (0.5*1000*v_2^2 )$

=> $v_2^2 = \frac{ (450 *10^{3}) + (1000 * 9.8 *0 ) + (0.5 * 1000 * 0.85^2) -[ (1000 * *9.8*3.70) ]}{0.5*1000}$

=> $v_2= \sqrt{ \frac{ (450 *10^{3}) + (1000 * 9.8 * 0) + (0.5 * 1000 * 0.85^2) -[ (1000 * *9.8*3.70) ]}{0.5*1000}}$

=> $v_2= 0.45 \ m/s$

4 0

3 years ago

The force exerted on an object when it is in contact with another object as it moves or tries to move is?

Paraphin [41]

I think that friction is the force exerted on an object when it is in contact with another object as it moves or tries to move.

6 0

3 years ago