Answer: final Displacement = 0 km, total distance covered =7 km
Explanation:
Given the following :
From home to library = 1.3 km East
Library to music store = 0.68km East
Music store to friend's house = 1.1km North
Friend's house to grocery store = 0.42 km North
Displacement is the net change in distance traveled.
Eastward distance :
To = (1.3 + 0.68)km = 1.98km East
Fro = (0.68 + 1.3)km = 1.98 km East
Δ distance = (1.98 - 1.98) = 0
Northward direction:
To = (1.1 + 0.42)km = 1.52km north
Fro = (0.42 + 1.1)km = 1.52km North
Δ distance = (1.98 - 1.98) = 0
Hence final Displacement = 0
Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5
= 7km
Answer:
Marie Curie
Explanation:
I hope to see you helped :D?
Answer:
<h3>The answer is 6 m/s²</h3>
Explanation:
The acceleration of an object given it's velocity and time taken can be found by using the formula
where
v is the velocity
t is the time
We have
We have the final answer as
<h3>6 m/s²</h3>
Hope this helps you
Your heart rate is higher than normal.
(a) The horizontal and vertical components of the ball’s initial velocity is 37.8 m/s and 12.14 m/s respectively.
(b) The maximum height above the ground reached by the ball is 8.6 m.
(c) The distance off course the ball would be carried is 0.38 m.
(d) The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.
<h3>
Horizontal and vertical components of the ball's velocity</h3>
Vx = Vcosθ
Vx = 39.7 x cos(17.8)
Vx = 37.8 m/s
Vy = Vsin(θ)
Vy = 39.7 x sin(17.8)
Vy = 12.14 m/s
<h3>Maximum height reached by the ball</h3>
Maximum height above ground = 7.51 + 1.09 = 8.6 m
<h3>Distance off course after 2 second </h3>
Upward speed of the ball after 2 seconds, V = V₀y - gt
Vy = 12.14 - (2x 9.8)
Vy = - 7.46 m/s
Horizontal velocity will be constant = 37.8 m/s
Resultant speed of the ball after 2 seconds = √(Vy² + Vx²)
<h3>Resultant speed of the ball and crosswind</h3>
<h3>Distance off course the ball would be carried</h3>
d = Δvt = (38.72 - 38.53) x 2
d = 0.38 m
The ball's velocity after 2.0 seconds if there is no crosswind is 38.53 m/s.
Learn more about projectiles here: brainly.com/question/11049671