The wording of this problem indicates that there was an illustration. Could you possibly share that illustration?
Working without an illustration:
If tan theta = 3, then tan theta = opp/adj = 3/1. This tells us that the opp side is 3 times as long as is the adj. side. Let x be the shorter side, i. e., let x represent the adjacent side; then y is the longer side and represents the opposite side.
Then y = 3x (the opp side is 3x the adj side in length).
Applying the Pyth. Thm. a^2 + b^2 = c^2,
x^2 + (3x)^2 = hyp^2 = (25 cm.)^2
So x^2 + 9x^2 = (625 cm^2)
10x^2 = 625 cm^2, or x^2 = (625 cm^2) / 10 = 62.5 cm^2
x = 7.91 cm. Therefore, y = 3(7.91) = 23.72 cm.
We were supposed to round off these answers to the nearest 10th cm.
Therefore, x = 7.9 cm and y = 23.7 cm
Would that be A, B, C or D?
L = 5+ 2W
LW= 250
you really only need 2 equations
but if you want you could also put
L+W = 35 cm
W= 10
L= 25
Answer:
a and c
Step-by-step explanation:
Answer:
Converting the equation 
into completing the square method we get: 
Step-by-step explanation:
we are given quadratic equation:
And we need to convert it into completing the square method.
Completing the square method is of form: 
Looking at the given equation
We have a = x
then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20
So, 20x in form of 2ab can be written as: 2(x)(10)
So, we need to add and subtract (10)^2 on both sides
So, converting the equation into completing the square method we get:
Answer:(15, 100)
Step-by-step explanation:
first find the coordinates of the point above (3, 20)
you just look at the x axis and where the point is in this case x would be 6 and then you find y which would be 40
so the coordinate would be (6, 40)
now subtract (6, 40) by (3, 20)
6-3= 3
40- 20= 20
you get the first coordnites which is what you add (12,80) to
12 +3= 15
80+ 20= 100
you get the coordinates (15, 100)
