This is your answer.... all you are doing is substituting what ever the variable is
Given:
The scale factor is 1:12.
Dimension of model = 32 cm
To find:
The actual dimension in m.
Solution:
Let x be the actual dimension.
The scale factor is 1:12 and the dimension of model is 32 cm.

On cross multiplication, we get


![[\because 1\ m=100\ cm]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%5C%20m%3D100%5C%20cm%5D)
Therefore, the actual dimension is 3.84 m.
Answer:
18x^2 - 9
Step-by-step explanation:
y = f(x)= 6x^3 - 9x + 4
dy/dx = d/dx(6x^3) - d/dx(9x) + d/dx (4)
=6.d/dx(x^3) - 9.d/dx (x) + d/dx. (4)
=6.3x^2 - 9.1 + 0 =18x^2 - 9
For E2020 users, the correct answer is A (No,<span>because </span>P<span>(F ∩ T) ≠ </span>P<span>(F) • </span>P<span>(T).)</span>
You do length times width times you get your area. (I think)