So really you only need to answer the first one because you have more than enough og everything. 2×(what)=14 then that will be your answer
Answer:
A. Adding another bulb will make the two of them light a little less brighter since the electrical flow is divided into two making them work.
B. There is a possibility that the flow of electricity maybe little due to the thickness of the wire. There could also be a rise in the temperature of the cell and the bulb.
C. The Bulb will shine brighter because of the extra power or electricity provided! Also, if the voltage is too much, expect the bulb to burn out or sadly, explode.
BTW GOODLUCK!!
watch 9-1-1 on Fox!
Isn’t it that you need UV or something?
Answer:
38.0 g C2F3Cl3) / (187.3756 g C2F3Cl3/mol) x (3 mol Cl / 1 mol C2F3Cl3) x (35.4532 g Cl/mol) =
21.6 g Cl in C2F3Cl3
Answer:- 12.7%
Solution:- It says, ammonium phosphate is 60.9%. It means if we assume 100 g of the sample then there is 60.9 g ammonium phosphate in it.
Formula of ammonium phosphate is
and it's molecular weight is 149 grams per mol. There is only one P in the formula and so the mass of P in 149 g of ammonium phosphate is 31 g(atomic mass of P).
Now, we could use the proportions to find out the mass percentage of P in the sample.
31 g P is present in 149 g of ammonium phosphate, how many grams of P would be present in 60.9 g of ammonium phosphate. Let's set the proportions as:



This 12.7 g of phosphorous is present in 100 g of the sample means there is 12.7% phosphorous in the sample.