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nekit [7.7K]
3 years ago
9

The compound HNO3 can be described as an

Chemistry
1 answer:
xz_007 [3.2K]3 years ago
6 0
The answer is (1) Arrhenius acid and an electrolyte. The HNO3 is a H+ ion donor and OH- receptor. Electrolyte means the compound will release ion when dissolving in suitable ionized solution.
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How many kJ are 3,340J?
forsale [732]
The answer I believe is 3.340kj.
8 0
3 years ago
Select which of the following are used to determine the age of the Earth. Select 3.
saveliy_v [14]

Meteorites discovered on earth

7 0
2 years ago
Which of these electron transitions correspond to absorption of energy and which to emission?
Keith_Richards [23]

The electron transitions representing absorption of energy are:

(a) n = 2 to n = 4

(d) n = 3 to n = 4

and those which represents emissions of energy are:

(b) n = 3 to n = 1

(c) n = 5 to n = 2

An electron emits energy when it jumps from a higher energy level to a lower energy level transitions.

An electron absorbs energy to jump from a lower energy level to a higher energy level transitions.

(a) n = 2 to n = 4

Here, the initial level (2) is lower than the final level (4).

Hence energy is absorbed.

(b) n = 3 to n = 1

Here, the initial level (3) is higher than the final level (1).

Hence energy is released.

(c) n = 5 to n = 2

Here, the initial level (5) is higher than the final level (2).

Hence energy is released.

(d) n = 3 to n = 4

Here, the initial level (3) is lower than the final level (4).

Hence energy is absorbed.

The question is incomplete. Find the complete question here:

Which of these electron transitions correspond to absorption of energy and which to emission?

(a) n = 2 to n = 4

(b) n = 3 to n = 1

(c) n = 5 to n = 2

(d) n = 3 to n = 4

Learn more about electron transitions at brainly.com/question/2079874

#SPJ4

4 0
1 year ago
3)<br>0.09 moles of sodium sulfate in 12 mL of solution.<br>​
adelina 88 [10]

Answer:

7.5 M

Explanation:

In order to find a solution's molar concentration, or molarity, you need to determine how many moles of solute, which in your case is sodium sulfate,  

Na

2

SO

4

, you get in one liter of solution.

That is how molarity was defined -- the number of moles of solute in one liter of solution.

So, you know that you have  

0.090

moles of solute in  

12 mL

of solution. Your goal here will be to scale up this solution by using this information as a conversion factor to help you determine the number of moles of solute present in

6 0
3 years ago
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