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Firlakuza [10]
3 years ago
9

If a small motor does 520 J of work to move a toy car 260 m in 3.0 seconds, how much power is being applied by the motor?

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

P = 173.33 [W]

Explanation:

Power is defined as the amount of work done over a given time.

W = work = 520 [J]

t = time = 3 [s]

P = power [w]

Therefore by working relationship over time we can calculate the power.

P =W/t\\P = 520/3\\P=173.33[W]

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A pure sound wave, generated by a tuning fork, is considered a periodic wave. Which statement is true for this tuning fork sound
soldier1979 [14.2K]

Answer : Every wave has the same wave pattern.

Explanation : A pure sound wave has a single frequency and its generated by a tuning fork . The sound wave is a  simple periodic wave.

When an object such as a guitar push and pull on the around it. When it pushes on the air, then the pressure increases and when it pull on the air,  then the pressure decreases and sound waves are formed.

Hence, sound wave has the same wave pattern.  

4 0
3 years ago
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A weather forecaster uses Doppler radar to predict the track of a storm near the town of hillville when the Doppler signal is he
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3 years ago
A satellite in outer space is moving at a constant velocity of 20.5 m/s in the +y direction when one of its on board thruster tu
Katyanochek1 [597]

Answer:

a)  V_f = 25.514 m/s

b)  Q =53.46 degrees CCW from + x-axis

Explanation:

Given:

- Initial speed V_i = 20.5 j m/s

- Acceleration a = 0.31 i m/s^2

- Time duration for acceleration t = 49.0 s

Find:

(a) What is the magnitude of the satellite's velocity when the thruster turns off?

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.

Solution:

- We can apply the kinematic equation of motion for our problem assuming a constant acceleration as given:

                                   V_f = V_i + a*t

                                   V_f = 20.5 j + 0.31 i *49

                                   V_f = 20.5 j + 15.19 i

- The magnitude of the velocity vector is given by:

                                   V_f = sqrt ( 20.5^2 + 15.19^2)

                                   V_f = sqrt(650.9861)

                                  V_f = 25.514 m/s

- The direction of the velocity vector can be computed by using x and y components of velocity found above:

                                 tan(Q) = (V_y / V_x)

                                 Q = arctan (20.5 / 15.19)

                                 Q =53.46 degrees

- The velocity vector is at angle @ 53.46 degrees CCW from the positive x-axis.

4 0
3 years ago
Does heat demagnetize?
Nastasia [14]

Answer:

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3 years ago
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son4ous [18]

Answer:

Explanation:

I think the answer is statement no 3.

Hope it helps.

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3 years ago
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