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uranmaximum [27]
3 years ago
13

Ajdaifsgodtistizhxtsgoachoach

Physics
1 answer:
Norma-Jean [14]3 years ago
8 0

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm maybe

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What is the acceleration of an object that has a mass of 10kg and is pushed with a force of 50n
worty [1.4K]

Answer:

5m/s/s

Explanation:

force = mass x acceleration

50 = 10a

a=5m/s/s

7 0
2 years ago
2. If a cyclist in the Tour de France traveled southwest a distance of 12,250 meters in one hour, what would the velocity of the
Luda [366]
  • Answer:

<em>12,25 km/h</em>

<em>≈ 3,4 m/s </em>

  • Explanation:

<em>v = d/t</em>

<em>= 12250m/h</em>

<em>= 12,25km/h</em>

<em>or</em>

<em>v = d/t</em>

<em>= 12250m/h</em>

<em>1h = 60m×60s = 3600s</em>

<em>= 12250m/3600s</em>

<em>≈ 3,4 m/s </em>

5 0
3 years ago
An object that is slowing down in a positive direction must have
zepelin [54]

Answer:

Positive velocity and negative acceleration

Explanation:

An object moving in the positive direction has a positive velocity.

An object that's slowing down while moving in the positive direction has a negative acceleration.

5 0
3 years ago
An ant carries a morsel of food 4.26 meters along a straight path to his nest. He then turns around and follows the path back to
Basile [38]
The displacement is zero. The most important concept to understand is the difference between displacement and total distance traveled. Total distance traveled would be tracking the length of the entire path the ant walked for the whole time (4.26m x 2). Displacement is how far from a designated origin (here, the food source) the ant ended up at the end of the time. Mathematically, the ant walked 4.26m from food source to nest (+4.26m) and then walked from the nest to food source (-4.26m), so the net displacement is [+4.26] + [-4.26] = 0m.
6 0
3 years ago
A sealed box contains a monatomic ideal gas. The number of gas atoms per unit volume is 5.00 * 1020 atoms&gt;cm3, and the averag
Veronika [31]

Answer:

Pressure,P=6×10^3Pa

Explanation:

The gas has an ideal gas behaviour and ideal gas equation

PV=NKT

T= V/N p/K ...eq1

Average transitional kinetic energy Ktr=1.8×10-23J

Ktr=3/2KT

T=2/3Ktr/K....eq2

Equating eq1 and 2

V/N p/K = 2/3Ktr/K

Cancelling K on both sides

P= 2/3N/V( Ktr)

Substituting the value of N/V and dividing by 10^-6 to convert cm^3 to m^3

P = 2/3 (5.0×10^20)/10^-6 × 1.8×10^-23

P= 6 ×10^3Pa

6 0
3 years ago
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