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2 years ago

Ajdaifsgodtistizhxtsgoachoach

Physics

1 answer:

Norma-Jean [14]2 years ago

8 0

Hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm maybe

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The creation of electricity in a coil of a wire through the movement of a magnet is called what?

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D. Electromagnetic Induction.

Explanation:

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2 years ago

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3 years ago

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At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . wh

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We have the equation for electric field E = kQ/ $d^{2}$

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to $d^{2}$

So, $\frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}$

$E_{1}$ = 485 N/C

$d_{1}$ = 0.208 cm

$d_{2}$ = 0.620 cm

$E_{2}$ = ?

$\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}$

$E_{2}$ = $\frac{485*0.208^{2}}{0.628^{2}}$

$E_{2}$ = 53.20 N/C

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3 years ago

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A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2

ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

$\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}$

And we need to find out the change in momentum of the body . Here ,

velocity before collision (u) = 10m/s
velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

$\sf\longrightarrow momentum (p)= mass(m) * velocity(v)$

Therefore change in momentum will be,

$\sf\longrightarrow \triangle p = mv - mu$

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

$\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\$

$\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s) \\$

$\sf\longrightarrow \Delta p = 0.1 kg * -12m/s \\$

$\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\$

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1 year ago

If two objects are moved farther apart, the force of gravity between them will

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It's Decrease or cease to exist, but I'm leaning more towards decrease.

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