Question

Calculate the heat energy required to increase the temperature of 3 kg of water by 20ºC. The specific heat capacity of water is 4200 J/ kg °C

Answer 1

Answer:

Heat energy required = 252000J or 252KJ.

Explanation:

Given the following data;

Mass = 3kg

Temperature = 20ºC

Specific heat capacity of water = 4200 J/kg°C

To find the heat energy required;

Heat capacity is given by the formula;

$Q = mct$

Where;

• Q represents the heat capacity or quantity of heat.
• m represents the mass of an object.
• c represents the specific heat capacity of water.
• t represents the temperature.

Substituting into the equation, we have;

$Q = 3*4200*20$

Q = 252000 Joules or 252 Kilojoules.