(A) It will 100 times larger than the original force.
In this problem, you are asked to find a vertical position of a ball when you are given its initial position on a spring. In both locations, the speed of the ball is zero.
If non-conservative forces are either known or small and if energy is converted from one form to another between the locations, then any time you relate speed and position of an object at two different points, conservation of energy is the most direct way to understand the problem.
In this case, you start out with stored energy in the compression of the spring and convert it to stored gravitational energy.
Hold up, hee-haw, whoa ! Back it up.
-- When Galileo decided to point his toy telescope at things
in the sky, he discovered moons circling the planet Jupiter.
Right now, in 2016, something like 65 moons of Jupiter are
known. Galileo saw four of them. You can see those too, if
you have binoculars and you know how to find Jupiter in the sky.
-- The Moons aren't "on" Jupiter; they follow orbits around it,
at some considerable distance from it.
-- Galileo didn't 'discover' Jupiter. Jupiter is quite visible to
the unaided eye, and has been for several thousand years.
That's a big part of the reason why Galileo decided to give it
a look-see with his telescope.
Answer:
ωf = 4.53 rad/s
Explanation:
By conservation of the angular momentum:
Ib*ωb = (Ib + Ic)*ωf
Where
Ib is the inertia of the ball
ωb is the initial angular velocity of the ball
Ic is the inertia of the catcher
ωf is the final angular velocity of the system
We need to calculate first Ib, Ic, ωb:
ωb = Vb / (L/2) = 16 / (1.2/2) = 26.67 m/s
Now, ωf will be:
The shaft is 78m approximately deep. The correct option is D which is 78 meters
<h3>
What are Sound Waves ?</h3>
Sound waves are longitudinal. That is, the direction of the waves is parallel to the direction of its propagation of particles.
Given that a boy finds an abandoned mine shaft in the woods, and wants to know how deep the hole is. He drops in a stone, and counts 4 seconds before he hears the "plunk" of the stone hitting the bottom of the shaft.
- The speed of the sound V = 330m/s
- The time it takes the sound to reach the top = t
Speed V = distance / time
330 = h/t
Make t the subject of formula
t = h/330
As the stone is dropped, initial velocity = 0, Using the formula
h = 1/2gT²
But T = 4 - t
T = 4 approximately
Substitute all the parameters
h = 1/2 × 9.8 × (4)²
h = 4.9 × (16)
h = 78.4m
Therefore, the shaft is 78m approximately deep. The correct option is D which is 78 meters
Learn more about sound wave here: brainly.com/question/16093793
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