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Mnenie [13.5K]
2 years ago
13

a square loop whose sides are long is made with copper wire of radius , assuming resistivity of copper is . if a magnetic field

perpendicular to the loop is changing at a constant rate of , what is the current in the loop?
Physics
1 answer:
OLEGan [10]2 years ago
4 0

A square loop whose sides are long is made of copper wire of radius , given the resistivity of copper is . if the magnetic field perpendicular to the loop changes at a constant rate of I = 14.029 mA.

The basic characteristic of a substance that measures how effectively it resists an electric current is called electrical resistance. A material with low resistance is a material that easily conducts electric current. A Greek letter is often used to indicate resistivity. Electrical resistance is a basic property of a material that measures how strongly it resists an electric current. The SI unit for electrical resistance is the ohmmeter.

We use magnetic field as a tool to describe how the magnetic field is distributed in the space around and inside something of a magnetic nature. A material with low resistance is a material that easily conducts electric current. A Greek letter is often used to indicate resistivity. An ohmmeter is a unit of electrical resistance in the SI system.

Learn more about magnetic field here;

brainly.com/question/24397546

#SPJ4

The complete question is :

A square loop whose sides are 6.0-cm long is made with copper wire of radius 1.0 mm. If a magnetic field perpendicular to the loop is changing at a rate of 5.0 mT/s, what is the current in the loop?

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3 years ago
An ideal transformer has 60 turns on its primary coil and 300 turns on its secondary coil. If 120 V at 2.0 A is applied to the p
Taya2010 [7]

Explanation:

It is given that,

Number of turns in primary coil, N_p=60

Number of turns in secondary coil, N_s=300

Voltage in primary coil, V_p=120\ V

Current in primary coil, I_p=2\ A

We have to find the voltage and current in the secondary coli. Firstly calculating the voltage in secondary coil as :

\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}

\dfrac{60}{300}=\dfrac{120}{V_s}

V_s=720\ Volts

Now, calculating the current present in the secondary coil as :

\dfrac{N_p}{N_s}=\dfrac{I_s}{I_p}

\dfrac{60}{300}=\dfrac{I_s}{2\ A}

I_s=0.4\ A

<em>Hence, this is the required solution.</em>

3 0
3 years ago
A 77 ton monolith is transported on a causeway that is 3500 ft long and has a slope of about 3.6 degrees. How much force paralle
const2013 [10]

Answer:

4.8 ton

Explanation:

We are given that

Mass,m=77 ton

Displacement,s=3500 ft

\theta=3.6^{\circ}

We have to find the force parallel to the incline would be required to hold the monolith on this causeway.

The force parallel to the incline would be required to hold the monolith on this causeway=Fsin\theta

Using the formula

The force parallel to the incline would be required to hold the monolith on this causeway=77sin3.6=4.8 Ton

7 0
3 years ago
A 1200-kg car traveling initially with a speed of 25.0 m/s in an easterly direction crashes into the rear end of a 9,000-kg truc
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Answer

given,

mass of car (m) = 1200 Kg

speed of cur, u = 25 m/s

mass of truck(M) = 9000 Kg

speed of truck, u' = 20 m/s

v = 18 m/s

a) using conservation of momentum

m u + M u' = m v + M v'

1200 x 25 + 9000 x 20 = 1200 x 18 + 9000 x v'

9000 v' = 188400

v' = 20.93 m/s

b) To calculate losses, we will find the kinetic energies before & after collision. Any difference would give us the losses (in energy form).

(K E)₁= (K E)₂+ Losses

losses = (K E)₂ -  (K E)₁

           =\dfrac{1}{2}(mv^2 + Mv'^2)- \dfrac{1}{2}(mu^2 + Mu'^2)

           =\dfrac{1}{2}(1200 \times18^2 +9000 \times 20.93^2)- \dfrac{1}{2}(1200 \times 25^2 +9000\times 20^2)

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6 0
3 years ago
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Answer:

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