<span>The better the RSM dissolves in the solvent, the higher the Rf (retention factor) will be, and the further the RSM will move. If the RSM is a polar compound, increasing the polarity of the solvent will increase the Rf of the RSM. If the RSM isn't a polar compound, an increasingly polar solvent will decrease the Rf.</span>

5 0

3 years ago

What is The pH and pOH of a 1.00x10-3M solution of CH3COOH (Ka=1.75x10-5) ?

zaharov [31]

Answer:

Explanation:

Since $CH _ 3COOH$ is a weak acid to find the pH of $CH _ 3COOH$ we use the formula

$pH = - \frac{1}{2} log(Ka) - \frac{1}{2} log(c)$

where

Ka is the acid dissociation constant

c is the concentration

From the question

Ka of $CH _ 3COOH$ = 1.75 × 10^-5

c = 1.00 × 10-³M

Substitute the values into the above formula and solve for the pH

That's

$pH = \frac{1}{2} ( - log(1.75 \times {10 }^{ - 5} - log(1.00 \times {10}^{ - 3} ) ) \\ = \frac{1}{2} (4.757 + 3) \\ = \frac{1}{2} \times 7.757) \\ = 3.8785 \: \: \: \: \: \: \: \:$

We have the answer as

To find the pOH we use the formula

pH + pOH = 14

pOH = 14 - pH

pOH = 14 - 3.9

We have the answer as

Hope this helps you

4 0

3 years ago

1. a) Name two examples of good conductors?

Pachacha [2.7K]

A. good conductors - copper, aluminium

b. fair conductors - carbon,human body

c. insulator - paper, wood

7 0

3 years ago