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m_a_m_a [10]
2 years ago
12

Chemical calculation. don't have to rush, take your time.

Chemistry
1 answer:
Kazeer [188]2 years ago
5 0

Answer:

what is the formula of rectangle

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Calculate the mass of a body<br>Whose volume is<br>Is 2cm3 and<br> density is 520cm3​
MrRissso [65]

Answer:

The answer is

<h2>1040g</h2>

Explanation:

Density = mass / volume

mass = density × volume

volume = 2cm³

density = 520g/cm³

mass = 2 × 520

= 1040g

Hope this helps you

6 0
3 years ago
Use a sheet of paper to answer the following question. Take a picture of your answers and attach to this assignment. Draw the st
pentagon [3]

Answer:

Explanation:

Structure of the 2,2,4,4-tetramethyl-3-pentanone is give in the attachment

In 2,2,4,4-tetramethyl-3-pentanone, no alpha hydrogen is present, therefore, enol form is not possible and hence, exist only in keto form.

Explanation for existence of cyclohexa-2,4-diene-1-one only in enol form:

keto form of cyclohexa-2,4-diene-1-one not aromatic and hence less stable.

Whereas enol form it is aromatic which makes it highly stable. that's why cyclohexa-2,4-diene-1-one exists only in enol form.

8 0
3 years ago
What is it called when the moon blocks the view from the sun?
defon

Answer:

solar eclipse

Explanation:

8 0
3 years ago
Read 2 more answers
which characteristics of an element can be determined by considering only the element’s specific location on the periodic table?
Nadusha1986 [10]

Answer:

Gas, Solid, or liquid

Explanation:

5 0
3 years ago
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Before we can use this equation for
AlexFokin [52]

Answer:

2C₂H₆ +  [7]O₂     →      [4]CO₂ + [6]H₂O

Explanation:

Chemical equation:

C₂H₆ +  O₂     →      CO₂ + H₂O

Balanced chemical equation:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Step 1:

2C₂H₆ +  O₂     →      CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C = 1

H = 12                                    H = 2

O = 2                                     O = 3

Step 2:

2C₂H₆ +  O₂     →      4CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 2

O = 2                                     O = 9

Step 3:

2C₂H₆ +  O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 2                                     O = 14

Step 4:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 14                                     O = 14

3 0
3 years ago
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