Phytoplankton, a specific type of microscopic producer, supplies up to 50% of Earth's oxygen.
Answer:
The sodium nitrate is more economical
Explanation:
Hi, to compare this two options you need to determine the amount of nitrogen per 100 lb of both and then estimate its cost:
1) Sodium nitrate ![NaNO_3](https://tex.z-dn.net/?f=NaNO_3)
This fertilizer has 30 % by weight of sodium nitrate:
![m=100 lb * 0.3= 30 lb=13.6 kg](https://tex.z-dn.net/?f=%20m%3D100%20lb%20%2A%200.3%3D%2030%20lb%3D13.6%20kg)
The molecular weight of sodium nitrate:
So, this salt has 14 g of N per 85 g:
![m_N=13600g*\frac{14g N}{85 g}=2240 g N](https://tex.z-dn.net/?f=m_N%3D13600g%2A%5Cfrac%7B14g%20N%7D%7B85%20g%7D%3D2240%20g%20N)
Cost per gram:
![C=\frac{9}{2240g}=0.004](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B9%7D%7B2240g%7D%3D0.004)
2) Ammonium sulfate ![NH_4SO_4](https://tex.z-dn.net/?f=NH_4SO_4)
This fertilizer has 20 % by weight of ammonium sulfate:
![m=100 lb * 0.2= 20 lb=9.07 kg](https://tex.z-dn.net/?f=%20m%3D100%20lb%20%2A%200.2%3D%2020%20lb%3D9.07%20kg)
The molecular weight of ammonium sulfate:
So, this salt has 14 g of N per 114 g:
![m_N=9070g*\frac{14g N}{114 g}=1113.8g N](https://tex.z-dn.net/?f=m_N%3D9070g%2A%5Cfrac%7B14g%20N%7D%7B114%20g%7D%3D1113.8g%20N)
Cost per gram:
![C=\frac{8.1}{1113.8g}=0.007](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B8.1%7D%7B1113.8g%7D%3D0.007)
Answer:
<h3>Avogadro's hypothesis states that two samples of gas of equal volume, at the same temperature and pressure, contain the same number of molecules. Avogadro's hypothesis allows chemists to predict the behavior of ideal gasses.</h3>
hope it helps
The balanced chemical equation is this:
Cl2(aq) + 2Br-(aq) --> 2Cl- + Br2(aq)
Looking at each substance involved in the reaction:
Cl2 has 0 charge and gains a charge of -1 after the reaction
Br- has a charge of -1 but turns to 0 after the reaction
Cl2 gained an electron which means it is the reduced substance
Br- lost an electron which means it is the oxidized substanced
Consequently, Cl2 is the oxidizing agent and Br- is the reducing agent.
HCl:
<span>
m=48,2g
M=36,5g/mol
n = m/M = 48,2g / 36,5g/mol = 1,32mol
1mol : 4mol
MnO</span>₂ + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O
0,86mol : 1,32mol
limiting reagent
0,33 will react
HCl is limiting reagent.