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Zarrin [17]
3 years ago
14

For a left-tailed test, the critical value of z so that a hypothesis test would reject the null hypothesis at 1% significance le

vel would be __________. Answer choices are rounded to the hundredths place. -1.03 -3.09 -2.33 -1.28
Mathematics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

C.-2.33

Step-by-step explanation:

We are given that

Significance level, \alpha =1%=0.01

We have to find  the critical value of z  for a left-tailed test.

To find the critical value , we will use the z-table at significance level 0.01 for left-tailed test.

By using the z-table at significance level 0.01 for left-tailed test

The critical value of z at  1% significance level for left-tailed test

=-2.33

We get p-value by using z-critical value

P-value=0.0099<0.01

So, hypothesis  test would be reject the null hypothesis at  at 1% significance level.

Hence, the critical value of z=-2.33

Option C is true.

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What is the LCD of 10 and 15?​
dem82 [27]

Answer:

The least common denominator, also called lowest common denominator (LCD), of 10 and 15 is 30.

Step-by-step explanation:

5 0
3 years ago
A model for tumor growth is given by the Gompertz equation dV dt = a (In b-, In V) V where a &gt;0 and b &gt;0 are constants and
Xelga [282]

Answer:

V(t) = b^{(1-e^{-at})}

Step-by-step explanation:

We are given the following information in the question:

\displaystyle\frac{dV}{dt} = a (In b - In V) V

where a > 0 and b > 0.

\displaystyle\frac{dV}{dt} = a (In b-In V) V\\\\\displaystyle\frac{dV}{dt} = -aV(ln\frac{V}{b})\\\\\frac{dV}{V(ln\frac{V}{b})} = (-a)dt\\\\\text{Put } ln\frac{V}{b} = z\\\\\text{Integrating both sides}\\\\\int \frac{dV}{V(ln\frac{V}{b})} = \int (-a)dt\\\\\text{We get}\\\\\int \frac{dz}{z} = \int (-a)dt\\\\\\\text{where C is the constant of integration}

V(0) = 1~ mm^3\\V(t) = b.e^{e^{-at+C}}\\\text{Putting t =0, V(0) = 1}\\\\V(0) = 1 = b.e^{e^{C}}\\\\V(t) = b^{(1-e^{-at})}

where v(t) is the required tumor volume as a function of time that has an initial tumor volume of V(0) = 1 cubic mm.

5 0
3 years ago
Solve for x. Show your work or explain your answer.
Alja [10]
X=2
x=15
4x+1=9
-1 -1
4x=8
4/4x=8/4=2

x/5-1=2
+1 +1
x/5=3
(5) (5)
x=15
8 0
3 years ago
If tan A = 4/5; what does CSC A =?<br> Round to nearest tenth.
ZanzabumX [31]

Answer:

1.6

Step-by-step explanation:

\tan \: A =  \frac{4}{5}  \\  \\  \cot \: A =   \frac{1}{ \tan \: A }  =  \frac{1}{ \frac{4}{5} }  =  \frac{5}{4}  \\  \\ csc\: A = \sqrt{1  +   {cot}^{2}\: A}     \\  =  \sqrt{1 +   { \bigg( \frac{5}{4}  \bigg)}^{2}  } \\  = \sqrt{1 +  \frac{25}{16} }   \\  = \sqrt{\frac{16 + 25}{16} }   \\  =   \sqrt{\frac{41}{16}}  \\  =  \frac{ \sqrt{41} }{4}  \\  =  \frac{6.40312424}{4}  \\  = 1.60078106 \\  \therefore \: csc \: A =1.6

6 0
3 years ago
Who can prove that ? :D<br><br> prove that lim x about 0 (sin(x)/x)=1<br> by using sandwich theorem
earnstyle [38]
cos (x)  \leq \frac{sin (x)}{x}  \leq 1

Apply limit as x->0
8 0
3 years ago
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