Answer:
137473735858884506343
Step-by-step explanation:
Answer:
10 seconds
Step-by-step explanation:
Every second the bug travels 0.5m/s or 0.5 meters per second.
Given that, every 2 seconds the bug will travel a full 1 meter.
To solve this one can simply divide 5m by 0.5 and get 10 seconds.
Answer:
3/4
Step-by-step explanation:
Fraction of names called last week = 1/4 of a page
Fraction called this week = 1/2 of a page
The number of pages worth of people called ;
This is an addition problem, as the total will be the sum. Of the fractions called this week and last week
Hence,
Total page worth of names called :
(1/4 + 1/2) = (1 + 2) / 4 = 3/4
119 divided by 9 is 13r22
702 divided by 9 is 78
432 divied by 9 is 48
641 divided by 9 is 71r22
<span>372 divided by 9 is 41r33</span>
:<span> </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)).
There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned.
Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".
Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s.
Plugging in t = 169 gives 2/13 cm3/s.</span>
