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Rainbow [258]
4 years ago
15

The molecule carbon disulfide (CS2) is nonpolar and has only London dispersion forces between the molecules. Carbon tetrachlorid

e (CCl4) is also nonpolar but is made of larger molecules that are more strongly affected by London dispersion forces. Based on this information, CS2 likely has a----- melting point and a---- vapor pressure when compared with CCl4.

Chemistry
2 answers:
Lorico [155]4 years ago
4 0

Answer:

PLATO: <u>Lower, Higher</u>

Explanation:

stepladder [879]4 years ago
3 0

Answer:

Final Answer: boiling point and high

Explanation:

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In which state of matter do the particles spread apart and fill all the space available to them?
xz_007 [3.2K]
Gas, as the particles have the most energy, and thus move the most.
7 0
3 years ago
Find the ratio of the volume divided by the
Nataly [62]

From the pair of values given, the ratio of the volume to the temperature for the first data pair is, 0.0026 cm³/K

<h3>What is a Ratio?</h3>

A ratio is a comparison between two quantities showing how much one quantity differs from another.

From the data given, the first data pair is as follows ;

  • Temperature = 276 K
  • Volume = 0.72 cm³

Ratio of volume to temperature = volume / temperature

Ratio = 0.72 / 276

Ratio = 0.002608 cm³/K

The significant figure's rule for division is the least number of significant figures used in the operation.

The least significant figure of the values given is 2.

Therefore, the ratio of the volume to the temperature for the first data pair is 0.0026 cm³/K

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4 0
2 years ago
In the laboratory a student determines the specific heat of a metal. She heats 19.6 grams of zinc to 98.37°C and then drops it i
fgiga [73]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc = 98.37 °C

Initial temperature of water = 24.16 °C

Final temperature of water (and zinc) = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate Specific heat of zinc

Heat lost by zinc = heat won by water

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

Qzinc = -Qwater

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

7 0
3 years ago
Pls help I will give u points pls
True [87]

Answer:

i think D

Explanation:

3 0
3 years ago
Read the given equation:NH3 + HCI —&gt; NH4CIWhich of the following is true about the equation?a) NH3 is the acid and NH4CI is t
Nutka1998 [239]

Explanation:

For the given equation:

NH3 + HCl -> NH4Cl

This is an acid-base reaction (neutralization): NH3 is a base, HCl is an acid and NH4Cl is the sal.

Answer: b) NH3 is the base and NH4CI is the salt.

8 0
1 year ago
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