All categories

3 years ago

Which is a physical characteristic of a fish?

Chemistry

1 answer:

Nitella [24]3 years ago

3 0

Answer:

Gill's

Explanation:

Fish's have many characteristics that differ from humans, and one of them is the gills.

You might be interested in

If Matteo has a model car with a volume of 100 mL and a mass of 200 g, what is the density of their model car?

OLEGan [10]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{200}{100} \\$

We have the final answer as

Hope this helps you

6 0

3 years ago

5. If a block of wood has a density of 0.6 g/cm3 and a mass of 120 g, what is its volume? (D= M/V)

AlexFokin [52]

Answer:

200 cm^3

Explanation:

V = M/D

V = 120g / (0.6g/cm^3)

V = 200 cm^3

4 0

3 years ago

At equilibrium, the concentrations in this system were found to be [ N 2 ] = [ O 2 ] = 0.200 M and [ NO ] = 0.600 M . N 2 ( g )

alexandr1967 [171]

Answer:

0.78 M

Explanation:

First, we need to know which is the value of Kc of this reaction. In order to know this, we should take the innitial values of N2, O2 and NO and write the equilibrium constant expression according to the reaction. Doing this we have the following:

N2(g) + O2(g) <------> 2NO(g) Kc = ?

Writting Kc:

Kc = [NO]² / [N2] * [O2]

Replacing the given values we have then:

Kc = (0.6)² / (0.2)*(0.2)

Kc = 9

Now that we have the Kc, let's see what happens next.

We add more NO, until it's concentration is 0.9 M, this means that we are actually altering the reaction to get more reactants than product, which means that the equilibrium is being affected. If this is true, in the reaction when is re established the equilibrium, we'll see a loss in the concentration of NO and a gaining in concentrations of the reactants. This can be easily watched by doing an ICE chart:

N2(g) + O2(g) <------> 2NO(g)

I: 0.2 0.2 0.9

C: +x +x -2x

E: 0.2+x 0.2+x 0.9-2x

Replacing in the Kc expression we have:

Kc = [NO]² / [N2] * [O2]

9 = (0.9-2x)² / (0.2+x)*(0.2+x) ----> (this can be expressed as 0.2+x)²

Here, we solve for x:

9 = (0.9-2x)² / (0.2+x)²

√9 = (0.9-2x) / (0.2+x)

3(0.2+x) = 0.9-2x

0.6 + 3x = 0.9 - 2x

3x + 2x = 0.9 - 0.6

5x = 0.3

x = 0.06 M

This means that the final concentration of NO will be:

[NO] = 0.9 - (2*0.06)

[NO] = 0.78 M

8 0

3 years ago

Cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

MAXImum [283]

<3333333333333333 >>:)))

Explanation:

5 0

2 years ago

Read 2 more answers

A long (i.e., L >> D) stainless steel rod 6.4 mm in diameter is initially at a uniform temperature of 25°C and is suddenly

sp2606 [1]

Answer:

68.4 seconds

Explanation:

Assume that the temperature of the stainless steel rod will reach 120 C in t seconds. According to lumped – capacity analysis use the following expression to determine the value of t

T- T∞/T₀ – T∞ = e^-(hA/ρcV)t, where T is the required temperature, T∞ is the surface temperature, T₀ is initial temperature of the rod, h is the convection heat transfer coefficient, A is surface are, ρ is density of stainless steel, c is specific head and V is the volume of the rod.

Area of rod = π x d x L and Volume of rod is (π/4) x d² L

T - T∞/T₀ – T∞ = e^-(h x π x d x L/ρc(π/4 x d² x L))t

T - T∞/T₀ – T∞ = e^-(4h/(ρ x c x d))t, d is the radius of the log and L is the length of rod

<em>The value of c and ρ for stainless steel can be obtained from the table of properties of metals</em>

<u>Substitute 120 C for T, 150 C for T∞, 25 C for T₀, 7817 kg/m³ for ρ, 460 J/kg.C for c, 6.4 x 10⁻³ m for d, 120 W/m².C for h in the above equation</u>

T - T∞/T₀ – T∞ = e^-(4h/ρ x c x d))t

120 – 150/25 – 150 = e ^ -(4 x 120/7817 x 460 x 6.4 x 10⁻³)t

0.24 = e^-0.02086t

<u>Take natural log on both sides</u>

㏑0.24 = -0.02086t

T = 68.4 seconds

Thus, the temperature of the stainless steel will reach 120 C in 68.4s

5 0

3 years ago