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serg [7]
3 years ago
10

suppose you want to treat if a sample compound is ionic. you have these materials: the solid compound, a glass container, a spoo

n, and a conductivity apparatus.what material is missing from your list, and why is it necessary?
Chemistry
2 answers:
Vsevolod [243]3 years ago
8 0

Answer:Sample Response: The missing material is water. You cannot test the conductivity of ionic compounds if they are not dissolved in water. Solid ionic compounds cannot conduct electricity.

Explanation:

xz_007 [3.2K]3 years ago
6 0
An ionic compound is a substance that contains atoms that are bonded together through an ionic bond, where electrons are transferred from one atom to another. For the given experiment above, the material that is missing from the list is WATER or solvent. It is necessary because conduction through water will help you identify if a sample compound is ionic through its electrolytes. <span>Ionic compounds that are soluble are typically electrolytes</span>
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Dry air is 78.08% nitrogen, 20.95% oxygen and 0.93% argon with the 0.04% being other gases. if the atmospheric pressure is 760.0
sveticcg [70]
Partial pressure (N2) = mole fraction * total pressure
 
{    1 mole of any ideal gas occupy same volume of 1 mole of any other ideal gas under same condition of temperature and pressure so mole fraction in the sample is simply 78.08%   =   0.7808   this is because equal volume of each gas has equal moles

partial pressure N2 = 0.7808 * 760 .0
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4 0
3 years ago
Read 2 more answers
Could someone help me with this?
Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

  • x is the oxidation number

#3

  • Purple as per the color of potassium permanganate

#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

7 0
2 years ago
Do you round when dividing significant figures
Tatiana [17]

Answer: You multiply and divide when rounding division significant figures

Explanation: Both multiplying and dividing significant figures have the same rule. That rule is, the FINAL ANSWER of a multiplication and division problem should be rounded to the number of significant figures that is the least amount of any figures used in the multiplication or division. Let us demonstrate below.

4 0
3 years ago
Ort
ivanzaharov [21]

Answer:

1 ethanol is right answer

Explanation:

CH3- CH2-OH

4 0
3 years ago
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Match each statements with the state of matter it describes?
Len [333]

Answer:

Solid  liquids , plasma gas

Explanation:

It retains its shape regardless of the shape of the container

5 0
2 years ago
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