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3 years ago

Micheal runs 7 miles in 80 minutes. At the same rate, how many miles would he run in 64 minutes?

1 answer:

7 0

Micheal's rate is 7 miles per 80 minutes, which can be written as a fraction:
7/80, which equals 0.0875.
Now you can say that Micheal runs 0.0875 miles per one minute.
Multiply 0.0875 by 64,
64(0.0875) = 5.6

Micheal would run 5.6 miles in 64 minutes.

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What is -7(x-2)=1=15-7x

Soloha48 [4]

Answer:

Step-by-step explanation:

Simplifying

-7(x + -2) + 1 = 15 + -7x

Reorder the terms:

-7(-2 + x) + 1 = 15 + -7x

(-2 * -7 + x * -7) + 1 = 15 + -7x

(14 + -7x) + 1 = 15 + -7x

Reorder the terms:

14 + 1 + -7x = 15 + -7x

Combine like terms: 14 + 1 = 15

15 + -7x = 15 + -7x

Add '-15' to each side of the equation.

15 + -15 + -7x = 15 + -15 + -7x

Combine like terms: 15 + -15 = 0

0 + -7x = 15 + -15 + -7x

-7x = 15 + -15 + -7x

Combine like terms: 15 + -15 = 0

-7x = 0 + -7x

-7x = -7x

Add '7x' to each side of the equation.

-7x + 7x = -7x + 7x

Combine like terms: -7x + 7x = 0

0 = -7x + 7x

Combine like terms: -7x + 7x = 0

0 = 0

Solving

0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

3 0

2 years ago

Find the length of the missing side. Leave your answer in simplest radical form.

lozanna [386]

Answer:

The other side is 7.48 yards.

Step-by-step explanation:

Given that,

Hypotenuse = 15 yards

One leg = 13 yards

We need to find the length of the other leg. We can use the Pythagoras theorem to find it such that,

$H^2=b^2+h^2$

Where

h is other leg

Put all the values,

$h=\sqrt{H^2-b^2} \\\\h=\sqrt{(15)^2-(13)^2} \\\\h=7.48\ yd$

So, the other side is 7.48 yards.

6 0

3 years ago

A 2X2 square is centered at the origin. It is dilated by a factor of 3. What are coordinates of the vertices of the square?

Vesna [10]

Answer:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

Step-by-step explanation:

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1), B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

B(1, -1) = 3(1, -1) = B'(3, -3)

C(1, 1) = 3(1, 1) = C'(3, 3)

D(-1, 1) = 3(-1, 1) = D'(-3, 3)

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3 years ago

Which fraction is equivalent to 56%?

HACTEHA [7]

14 / 45

56 / 100 reduces to 14 / 45

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3 years ago

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