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Drupady [299]
3 years ago
9

A car accelerates from rest, and travels 400 m in 3.5 seconds. If

Physics
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

A car accelerates from rest, and travels 400 m in 3.5 seconds. If

the net force on the car is 12,000 N what is the mass of the car? bzgs dvd d dv dvdvd dhd dbvd

Explanation:

shd dhd bdvd dhdbduhdbdhdbbdceudd f

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Identify two factors you must know to describe the motion of an object along a straight line
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In order to describe motion along a straight line, you must state the speed and direction of the motion. Those two quantities, together, comprise what's known as "velocity".

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3 years ago
In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin
alexandr402 [8]

Answer:

a) v=0.999124c

b) E=7.566*10^{22}

c) E_a=760 times\ larger

Explanation:

From the question we are told that

Distance to Betelgeuse d_b=430ly

Mass of Rocket M_r=20000

Total Time in years traveled T_d=36years

Total energy used by the United States in the year 2000 E_{2000}=1.0*10^20

Generally the equation of speed of rocket v mathematically given by

v=\frac{2d}{\triangle t}

v=860ly/ \triangle t

where

\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}

\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}

\triangle t=\sqrt{(860)^2+(36)^2}

\triangle t=860.7532

Therefore

v=\frac{860ly}{ 860.7532}

v=0.999124c

b)

Generally the equation of the energy E required to attain prior speed mathematically given by

E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2

E=7.566*10^{22}

c)Generally the equation of the energy E_a required to accelerate the rocket mathematically given by

E_a=\frac{E}{E_{2000}}

E_a=\frac{7.566*10^{22}}{1.0*10^{20}}

E_a=760 times\ larger

8 0
3 years ago
NEED HELP ASAP<br><br>ONLY ANSWER IF YK THE ANSWERS
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Answer:

there yah go that's the answer

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How does light travel across the universe to earth?
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