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2 years ago

A stone of mass 0.2 kg falls with an acceleration of 10.0 m/s. How big is the force that causes this acceleration?

Physics

1 answer:

Kobotan [32]2 years ago

4 0

Answer:

$\boxed {\boxed {\sf 2 \ Newtons}}$

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F= m \times a$

The mass of the stone is 0.2 kilograms and the acceleration is 10.0 meters per square second.

m= 0.2 kg
a= 10.0 m/s²

Substitute the values into the formula.

$F= 0.2 \ kg * 10.0 \ m/s^2$

Multiply.

$F=2 \ kg*m/s^2$

Convert the units.

1 kilogram meter per square second (kg*m/s²) is equal to 1 Newton (N)
Our answer of 2 kg*m/s² is equal to 2 N

$F= 2 \ N$

The force is <u>2 Newtons.</u>

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1 year ago

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2 years ago

Which bike rider has the greatest momentum?

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My guesses would be g. or F

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2 years ago

You are driving your 1700 kg car at 21 m/s down a hill with a 5.0∘ slope when a deer suddenly jumps out onto the roadway. You sl

podryga [215]

Answer:

d = 27.7 m

Explanation:

Here the car is driving on the inclined plane

So here we can say that work done by the gravity and work done by friction is equal to change in kinetic energy of the system

So here we can write it as

$mgsin\theta \times d - F_f \times d = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

now we have

m = 1700 kg

$v_f = 0$

$v_i = 21 m/s$

$F_f = 1.5 \times 10^4 N$

$(1700)(9.81)sin5 (d) - (1.5\times 10^4)d = 0 - \frac{1}{2}(1700)(21^2)$

$1453.5 d - (1.5\times 10^4)d = -374850$

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2 years ago

Write a question about how changing temperature affects gas

Lera25 [3.4K]

Answer:

"How does the volume of a gas kept at constant pressure change as its temperature is increased?"

Explanation:

One possible question can be:

"How does the volume of a gas kept at constant pressure change as its temperature is increased?"

The answer to this question is contained in Charle's law, which states that for a gas at constant pressure, the volume of the gas is proportional to its absolute temperature:

$V\propto T$

Or also written as

$\frac{V}{T}=const.$

By looking at this equation, we can find immediately the answer to our question: as the (absolute) temperature of the gas increases, the volume increases as well, by the same proportion.

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2 years ago