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Lera25 [3.4K]
3 years ago
7

A 125kg automobile with a tangential speed of 48.0 km/h follows a circular road that has a radius of 35.0m how large is the cent

ripetal force
Physics
1 answer:
Gnoma [55]3 years ago
7 0

Answer:

Centripetal force = 634.6  newton

Explanation:

Given that,

Weight of the automobile, M = 125 Kg

The tangential speed of the automobile, V = 48 Km/h

                                                             V = 13.33 m/s

The radius of the circular road, R = 35 m

The centripetal force is given by the relation

                        Fc = MV²/R

Where  M - the mass of the body

             V - velocity of the body

             R - Radius of its trajectory

Substituting in the above equation

                       Fc = 125 Kg x 13.33² m²/s²    /    35 m

                            = 22211.11 / 35  newton

                            = 634.6  newton

Hence, the centripetal force acting on the automobile is 634.6 N

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Answer:

F=-18412.9N, where the minus indicates the direction is opposite to that of the throw.

Explanation:

a)

Since MKS stands for meter-kilogram-second and we know that:

1\ hour = 3600\ seconds

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We can write that:

\frac{1\ hour}{3600\ seconds}=1

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These are conversion factors, equal to 1, so multiplying our results by them won't change their value, only their units.

So we have that:

90 mph=90 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=40m/s

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145 g=145 g(\frac{1kg}{1000g})=0.145kg

b)

Newton's 2nd Law tells us that F=ma, and the definition of acceleration is a=\frac{\Delta v}{\Delta t}, so we have:

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Taking the throw direction as the positive one, for our values we have:

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4 0
3 years ago
When you are ice skating, to get started, you push your stake backwards on the ice and, as a result, begin to move forward. whic
LUCKY_DIMON [66]

C. Newtons third law of motion

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If an X-ray beam of wavelength 1.4 × 10-10 m makes an angle of 20° with a set of planes in a crystal causing first order constru
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Answer:

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The relation between the distance of the slits and the angle through which it is passed is:

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As d and λ are constant

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Its negative
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