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3 years ago

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Two spheres have identical charges and are 75 cm apart. the force between them is +0.30 n. what is the magnitude of the charge o

n each sphere? (let x = charge) what can you tell about the charge signs on the spheres? ______________

1 answer:

ella [17]3 years ago

5 0

Answer:

$4.33\cdot 10^{-6}C$ , charges are both positive or both negative

Explanation:

The electrostatic force between the two spheres is given by

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the charges on the two spheres

r is the distance between the centres of the two spheres

In this problem, we have

$F=+0.30 N$ is the force

$r=75 cm=0.75 m$ is the distance between the spheres

$q_1 =q_2 =q$ because the two spheres have identical charge

Solving the formula for q, we find

$q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(+0.30 N)(0.75 m)^2}{9\cdot 10^9}}=4.33\cdot 10^{-6}C$

And the two charges have the same sign (so, both positive or both negative), since the sign of the force is positive (+0.30 N), so it is a repulsive force.

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The swinging pendulum has 10 joules of potential energy at its maximum height at points (1) and (5). If the mass of the pendulum

SVEN [57.7K]

The speed of the pendulum at point 3 is 1.4 m/s

Explanation:

We can solve this problem by using the law of conservation of energy. In fact, the mechanical energy of the pendulum (which is the sum of his potential energy + his kinetic energy) must be conserved. So we can write:

$U_1 +K_1 = U_3 + K_3$

where

$U_1$ is the initial potential energy, at the highest position

$K_1$ is the initial kinetic energy, at the highest position

$U_3$ is the final potential energy, at the lowest position

$K_3$ is the final kinetic energy, at the lowest position

We are told that:

$U_1 = 10 J$ is the potential energy of the pendulum at the maximum height

$K_1 = 0$ (when the pendulum is at maximum height, the speed is zero, so the kinetic energy is zero)

$U_3 = 0$ (potential energy is zero at the lowest position)

Therefore,

$K_3 = U_1 = 10 J$

Kinetic energy can be rewritten as

$K_3 = \frac{1}{2}mv^2$

where

m = 10 kg is the mass of the pendulum

v is its speed at point 3

Solving for v,

$v=\sqrt{\frac{2K_3}{m}}=\sqrt{\frac{2(10)}{10}}=1.4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

4 0

3 years ago

A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k

Bad White [126]

Answer:

$v_{f,w} = 1.791\,\frac{m}{s}$ , $v_{f,c} = 0.972\,\frac{m}{s}$

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

$I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}$

The final angular speed is:

$\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}$

$\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev} \right)$

$\omega_{f} \approx 5.116\,\frac{rad}{s}$

The tangential velocities of the wheel and the clay are, respectively:

$v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )$

$v_{f,w} = 1.791\,\frac{m}{s}$

$v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )$

$v_{f,c} = 0.972\,\frac{m}{s}$

5 0

3 years ago

Please help me out

Licemer1 [7]

Answer:

C

Explanation:

Because you would need to be able to handle the weight to move it.

3 0

4 years ago

a body accelerates uniformly from rest at 2m/s^2 for 5 seconds. Calculate its averege velocity in this time

Lana71 [14]

HERE IS YOUR ANSWER!

8 0

3 years ago

Someone please help me

Basile [38]

Photosynthesis is the name given to the set of chemical reactions performed by plants to convert energy from the sun into chemical energy in the form of sugar. Specifically, plants use energy from sunlight to react carbon dioxide and water to produce sugar (glucose) and oxygen. Many reactions occur, but the overall chemical reaction for photosynthesis is:

6 CO2 + 6 H2O + light → C6H12O6 + 6 O2
So it would be C, I hope this helped! :)

8 0

3 years ago