Answer:
The acceleration is 8 m/s²
Explanation:
The given parameters are;
The initial velocity, u = 2 m/s
The final velocity, v = 6 m/s
The distance the acceleration took place, s = 2 m
The acceleration, a, can be found from the following kinematic equation;
v² = u² + 2·a·s
By substituting the values, we have;
6² = 2² + 2 × a × 2
6² - 2² = 2 × a × 2
32 = 4·a
a = 32/4 = 8 m/s²
The acceleration, a, of the given motion = 8 m/s².
