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stiv31 [10]
3 years ago
7

Will mark brainliest

Physics
1 answer:
Genrish500 [490]3 years ago
8 0

The blue line with triangles are a cold front. The red line with half circles are a warm front. The black H is high pressure. The black L is low pressure. The black dot is overcast skies. Finally the white circle with a line down and 4 lines off of that line is 40-knot wind

idk and dont understand

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A car going at 30 m/s undergoes an acceleration of 2 m/s^2 for 4 seconds. What is it's final speed? How far did it travel while
Eva8 [605]
In this situation we need to use an kinematics equation. Usually I get questions about what is final velocity not speed.
KINEMATIC EQUATION:
Final velocity= initial velocity + acceleration×time

Substitute factors
Final velocity= 30 + 2(4)
Multiply
Final velocity= 30 + 8
Now add
Final velocity (or final speed)= 38 m/s

Now you want to find how long did it travel, we have to use another kinematics equation
KINEMATIC EQUATION:
Distance= initial velocity×time + (1/2)×acceleration× time squared

Substitute
distance= 30(4) + (1/2)(30)(4^2)
Multiply
distance= 120 + (15)(16)
distance= 120 + 240
distance= 360 m

5 0
3 years ago
Read 2 more answers
Is a meteor a fixed point of light?
lys-0071 [83]

Answer:

a meter fix point I guees

5 0
3 years ago
Atwood machine. A 20kg box and a 30kg crate are attached to the two ends of a massless string that passes over a massless fricti
Verdich [7]

Answer with Explanation:

We are given that

m_1=20 kg

m_2=30 kg

We have to find the acceleration of the system and the tension in the string.

30g-T=30a...(1)

T-20g=20a

T=20a+20g...(2)

Using equation (2) in equation (1)

30g-(20a+20g)=30a

30g-20a-20g=30a

10g=30a+20a=50a

a=\frac{10g}{50}=\frac{10\times 9.8}{50}=1.96 m/s^2

Where g=9.8m/s^2

Using the value of a in equation (2)

T=20(a+g)=20(1.96+9.8)=235.2 N

5 0
3 years ago
Which of the following accurately describes the process of Gas Exchange? *
Marrrta [24]

Answer:

<u><em>2.</em></u>

<u><em>Oxygen in your alveoli is diffused in to your blood and Carbon Dioxide is taken out of the blood and into the lungs</em></u>

Explanation:

Hope this helps:)

8 0
3 years ago
If a 110-W lightbulb emits 2.5 % of the input energy as visible light (average wavelength 550 nm) uniformly in all directions. P
pogonyaev

Answer:

9.7 x 10¹¹ .

Explanation:

2.5 % of 110 W = 2.75 J/s

energy of one photon

= hc / λ

=\frac{6.6\times10^{-34}\times3\times10^8}{550\times10^{-9}}

= .036 x 10⁻¹⁷ J

No of photons emitted

= 2.75 / .036 x 10⁻¹⁷

= 76.38 x 10¹⁷

Now photons are uniformly distributed in all directions so they will pass through a spherical surface of radius 2.8 m at this distance

photons passing per unit area of this sphere

= 76.38 x 10¹⁷  / 4π ( 2.8)²

Through eye which has surface area of π x ( 2 x 10⁻² )² m² , no of photons passing

= \frac{76.38\times10^{17}}{4\pi\times(2.8)^2} \times\pi(2\times10^{-3})^2

= 9.7 x 10¹¹ .

4 0
3 years ago
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