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3 years ago

Will mark brainliest

1 answer:

8 0

The blue line with triangles are a cold front. The red line with half circles are a warm front. The black H is high pressure. The black L is low pressure. The black dot is overcast skies. Finally the white circle with a line down and 4 lines off of that line is 40-knot wind

idk and dont understand

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S27253129 ,,, message me please, I can't ask you my homework question in the comments :c

Serjik [45]

What’s the problem what do u need help on

7 0

3 years ago

Electromagnetic force is carried between particles of matter by<br> particles named what

xz_007 [3.2K]

Answer:

gluons

Explanation:

please like and Mark as brainliest

8 0

4 years ago

Make a conclusion on the relationship of mass to the rate of the change of motion of the balloon at a constant force.

sasho [114]

At a constant force, the mass of the balloon is inversely proportional to the rate of change motion of the balloon.

The force applied to an object can be determined by applying Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

$F = m\frac{\Delta v}{t} \\\\\frac{F}{\frac{\Delta v}{t} } = m$

The mass of an object is inversely proportional to the rate of change motion of the object.

Thus, we can conclude that at constant force, the mass of the balloon is inversely proportional to the rate of change motion of the balloon.

Learn more here:brainly.com/question/19887955

6 0

3 years ago

Select the correct answer from each drop-down menu.

-Dominant- [34]

Answer:

And the force of ( Attraction or repulsion) between the poles A and D ( maximum or minimum)

4 0

3 years ago

Read 2 more answers

Suppose that a nascar race car is moving to the right with a constant velocity of +86 m/s. What is the average acceleration of t

Stels [109]

(a) As the car is moving with constant velocity, it means the rate change of velocity does not change, therefore the average acceleration of the car is zero.

Thus, there is no acceleration, when velocity is constant.

(b) Average acceleration,

$a =\frac{ v-u}{\Delta t}$

Here, v is final velocity and u is the initial velocity and $\Delta t$ is the time interval.

As twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed, therefore

$a =\frac{ -86 \ m/s-86 \ m/s }{12 \ s} = - 14 .3 \ m/s^2$

Thus, the average acceleration of the car is $14 .3 \ m/s^2$ in the direction to the left.

6 0

3 years ago