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2 years ago

(2 - 1 1/3) X 3/4 full answer pls

Mathematics

2 answers:

sammy [17]2 years ago

7 0

Answer:

0.5

Step-by-step explanation: can you give me brainleast hope this helped

mihalych1998 [28]2 years ago

6 0

12 83 cicnejwdhwigi3giu2

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Shelly is trying to improve her running time for a track race she ran the first race in 43.13 seconds her time was 43.1 seconds

lesantik [10]

I we consider her running times as an arithmetic series with common difference:
43.13 - 43.1 = -.03/2 = -.015, Shelly's time in the fourth race will be 43.1 - .015 = 43.085.

7 0

3 years ago

Read 2 more answers

Does it make sense? In my data set of 10 exam scores, the mean turned out to be the score of the person with the third highest g

san4es73 [151]

Answer:

Yes

Step-by-step explanation:

Given that In my data set of 10 exam scores, the mean turned out to be the score of the person with the third highest grade.

No two people got the same score.

Let the scores be a,b,c,d,e in ascending order where no two scores are equal

If a+b=d+e =2c then we can have c as the mean of the scores of 5 persons

This is because

Total sum = a+b+c+d+e = (a+b)+c+(d+e)

= 2c+c+2c=5c

Average= 5c/5 = c

It makes sense and there are chances as long as the above condition is satisfied.

8 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

2 years ago

How do u work this out and what's the answer

I am Lyosha [343]

1) you would need to turn both fractions so they have a common denominator, that would be 2 2/4 and 3/4
2) then subtract : 2 2/4 - 3/4, and you would subtract numerators and the whole number, but you keep the denominator the same. However, you cannot subtract 2 and 3 in this case, so you need to change 2 2/4 to 1 5/4 (they are still equivalent)
3) 1 5/4 - 3/4 = 1 2/4, which simplified version is 1 1/2
Therefore, the answer is 1 and 1/2

6 0

3 years ago

What is the solution to the equation fraction 1 over 4x = 5?

AVprozaik [17]

$\displaystyle \frac{1}{4x}=5\quad \Big|\cdot 4x\\\\1=20x\quad\Big|:20\\\\x= \frac{1}{20}$

7 0

2 years ago