Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm
Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side
For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm
If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm
Answer:
5.66 inches
Step-by-step explanation:
a² + 7² = 9²
a² + 49 = 81
a² + 49 - 49 = 81 - 49
a² = 32
a = square root of 32
a = 5.6568 or 5.66 inches
I used the Pythagorean Theorem to solve this.
Answer:
5
or
square root of 25
Step-by-step explanation:
I used my ti-84 plus ce calculator to solve
>download DISTMID
>prgm
>DISTMID
>DISTENCE
>enter points
>answer
S(5) = -16*(5)*2 + 550 = 390
you just replace t with 5
