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krok68 [10]
3 years ago
10

HELP PLZ!CHEMISTRY.WILL GIVE BRAINLIEST!!!!

Chemistry
2 answers:
Delicious77 [7]3 years ago
6 0

Answer:

welcome to 2021 dude

its been a long time since i answered this but here is my new account

Explanation:

Andrej [43]3 years ago
3 0

1. 12 L = 12 dm³

2. 3.18 g

<h3>Further explanation</h3>

Given

1. Reaction

K₂CO₃+2HNO₃⇒ 2KNO₃+H₂O+CO₂

69 g K₂CO₃

2. 0.03 mol/L Na₂CO₃

Required

1. volume of CO₂

2. mass Na₂CO₃

Solution

1. mol K₂CO₃(MW=138 g/mol) :

= 69 : 138

= 0.5

mol ratio of K₂CO₃ : CO₂ = 1 : 1, so mol CO₂ = 0.5

Assume at RTP(25 C, 1 atm) 1 mol gas = 24 L, so volume CO₂ :

= 0.5 x 24 L

= 12 L

2. M Na₂CO₃ = 0.03 M

Volume = 1 L

mol Na₂CO₃ :

= M x V

= 0.03 x 1

= 0.03 moles

Mass Na₂CO₃(MW=106 g/mol) :

= mol x MW

= 0.03 x 106

= 3.18 g

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How many moles of oxygen are necessary to generate 28 moles of water, according to the following equation: 2H2+O2→2H2O
valentinak56 [21]

The number of moles of oxygen required to generate 28 moles of water from the reaction is 14 moles

<h3>Balanced equation </h3>

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

2 moles of water were obtained from 1 mole of oxygen

<h3>How to determine the mole of oxygen needed </h3>

From the balanced equation above,

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Therefore,

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Thus, 14 moles of oxygen are needed for the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

5 0
2 years ago
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kondaur [170]

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Explanation:

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