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Stels [109]
4 years ago
11

Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below.

Chemistry
2 answers:
Zina [86]4 years ago
8 0

Answer:

15.63

Explanation:

i just took it on edgeunity

zavuch27 [327]4 years ago
7 0

15.63 mol. You need 15.63 mol HgO to produce 250.0 g O_2.

<em>Step 1</em>. Convert <em>grams of O_2 to moles of O_2</em>

Moles of O_2 = 250.0 g O_2 × (1 mol O_2/32.00 g O_2) = 7.8125 mol O_2

<em>Step 2</em>. Use the molar ratio of HgO:O_2 to convert <em>moles of O_2 to moles of HgO </em>

Moles of HgO = 0.8885 mol O_2 × (2 mol HgO/1 mol O_2) = <em>15.63 mol HgO</em>

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zheka24 [161]

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4 0
3 years ago
Read 2 more answers
PLEASE HELP I NEED THIS ANSWERED IN 10 MINS PLEASE
elena-14-01-66 [18.8K]
We are given the equation to use which is:
ΔG = ΔH - TΔS

We are also given that:
ΔG = 173.3 kJ
T = 303 degrees kelvin
ΔH = 180.7 kJ

Substitute with these givens in the above equation to get ΔS as follows:
ΔG = ΔH - TΔS
173.3 = 180.7 - 303ΔS
303ΔS = 180.7 - 173.3 
303ΔS = 7.4
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Based on the above calculations, the correct choice is:
D. 24.42 J/K
4 0
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