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Sauron [17]
2 years ago
7

A block of metal has a width of 3.2 cm , a length of 17.1 cm , and height of 4.6 cm . Its mass is 1.4 kg . Calculate the density

of the metal.
Express your answer to two significant figures and include the appropriate units.
Chemistry
1 answer:
dsp732 years ago
3 0

The Density of  the metal  is 5.6 g/cm³

<h3>What is the density of a substance?</h3>

The density of a substance is the ratio of the mass and the volume of the substance.

  • Density = mass/volume


The density of the metal is calculated as follows:

mass of metal = 1.4 kg = 1400 g

volume of metal = 3.2 * 17.1 * 4.6 = 251.712 cm³

Density of metal = 1400 g/251.712 cm³

Density of the metal  = 5.6 g/cm³

Therefore, the density of the metal is obtained from the mass and the volume of the metal.

Learn more about density at: brainly.com/question/1354972

#SPJ1

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Determine the heat needed to warm 25.3 g of copper from 22 degrees celsius to 39 degrees celsius.
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Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed  or heat lost

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We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

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Heat absorbed by the copper :

Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

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Answer:

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2. Q = 1.5 kJ

Explanation:

Hello there!

In this case, according to the given information for this calorimetry problem, we can proceed as follows:

1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:

1cal=4.184J\\\\1kJ=1000J

Then, we perform the conversion as follows:

600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ

2. Here, we use the general heat equation:

Q=mC(T_2-T_1)

And we plug in the given mass, specific heat and initial and final temperature to obtain:

Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ

Regards!

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