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Sauron [17]
1 year ago
7

A block of metal has a width of 3.2 cm , a length of 17.1 cm , and height of 4.6 cm . Its mass is 1.4 kg . Calculate the density

of the metal.
Express your answer to two significant figures and include the appropriate units.
Chemistry
1 answer:
dsp731 year ago
3 0

The Density of  the metal  is 5.6 g/cm³

<h3>What is the density of a substance?</h3>

The density of a substance is the ratio of the mass and the volume of the substance.

  • Density = mass/volume


The density of the metal is calculated as follows:

mass of metal = 1.4 kg = 1400 g

volume of metal = 3.2 * 17.1 * 4.6 = 251.712 cm³

Density of metal = 1400 g/251.712 cm³

Density of the metal  = 5.6 g/cm³

Therefore, the density of the metal is obtained from the mass and the volume of the metal.

Learn more about density at: brainly.com/question/1354972

#SPJ1

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A reaction of 41.9 g of Na and 30.3 g of Br2 yields 36.4 g of NaBr . What is the percent yield?
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Answer: The percent yield is, 93.4%

Explanation:

First we have to calculate the moles of Na.

\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles

Now we have to calculate the moles of Br_2

{\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles

{\text{Moles of } NaBr} = \frac{\text{Mass of } NaBr }{\text{Molar mass of } NaBr} =\frac{36.4g}{103g/mole}=0.353moles

The balanced chemical reaction is,

2Na(s)+Br_2(g)\rightarrow 2NaBr

As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = \frac{2}{1}\times 0.189=0.378 moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

As, 1 mole of bromine give = 2 moles of Sodium bromide

So, 0.189 moles of bromine give = \frac{2}{1}\times 0.189=0.378 moles of Sodium bromide

Now we have to calculate the percent yield of reaction

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100=\frac{0.353 mol}{0.378}\times 100=93.4\%

Therefore, the percent yield is, 93.4%

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