Answer:
Fluorine
General Formulas and Concepts:
<u>Chemistry</u>
- Reading a Periodic Table
- Periodic Trends
- Electronegativity - the tendency for an element to attract an electron to itself
- Z-effective and Coulomb's Law, Forces of Attraction
Explanation:
The Periodic Trend for Electronegativity is up and to the right of the Periodic Table.
Fluorine is Element 9 and has 9 protons. Radium is Element 88 and has 88 protons. Therefore, Radium has a bigger Zeff than Flourine.
However, since Radium is in Period 7 while Fluorine is in Period 2, Radium has more core e⁻ than Fluorine does. This will create a much larger shielding effect, causing Radium's outermost e⁻ to have less FOA between them. Fluorine, since it has less core e⁻, the FOA between the nucleus and outershell e⁻ will be much stronger.
Therefore, Fluorine would attract an electron more than Radium, thus bringing us to the conclusion that Fluorine has a higher electronegativity.
Answer:
Is [h] really [H]? What characteristics are mentioned?
Explanation:
A high [H} means high acid concentration.
Answer:
agribusiness system
Explanation:
<em><u>Have </u></em><em><u>a </u></em><em><u>good </u></em><em><u>day</u></em>
<em><u>thank </u></em><em><u>me </u></em><em><u>later</u></em>
<em><u>carryonlearing </u></em>
Answer: a rection will most likely occur if the colliding partilces have the proper orientation and energy.
The reactions occur becasue the molecules collide.
But not all the collisions result in a reaction.
The collisions have to meet some requirements.
Two of the basic requirements is that the collision has enough energy to overcome the activation energy and that the molecules collide in the riight way.
When two molecules react it is necessary that one element of one of the molecules interact when a specific element or group in the other molecule. That is the orientation must be the right one.
Collisions that to not have the proper orientation or enough energy will not cause reaction (changes in the bonds of the molecules).
N⁻²2H4(l) + 2H2O⁻¹2(l) → N⁰2(g) + 4H2O⁻²(g)
N is oxidized and O is reduced
