The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
<h3>Ratio of the areas of similar figures </h3>
From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>
<u />
The two figures are similar
From one of the theorems for similar polygons, we have that
If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²
Let the base length of the first figure be ,m = 14 mm
and the base length of the second figure be, n = 7 mm
∴ The ratio of their areas will be
![(\frac{14 \ mm}{7 \ mm})^{2}](https://tex.z-dn.net/?f=%28%5Cfrac%7B14%20%5C%20mm%7D%7B7%20%5C%20mm%7D%29%5E%7B2%7D)
![= \frac{196 \ mm^{2} }{49\ mm^{2} }](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B196%20%5C%20mm%5E%7B2%7D%20%7D%7B49%5C%20mm%5E%7B2%7D%20%7D)
![=\frac{4}{1}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4%7D%7B1%7D)
= 4:1
Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446
can you get a clearer picture pls
the bottom is to blurry
42-x=58
or, -x=58-42
with change in side sign also chamges we change sides to make like terms in one side and unlike in amother side.
or, -x= 16
or,x=-16.
therefore x=-16...
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>
Answer:
-2
Step-by-step explanation:
Equation of slope intercept form
y = (slope × x) + y intercept
Answer:
y=6x is the answer
Step-by-step explanation: