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adell [148]
3 years ago
15

Solve 2|x + 2| – 3 ≥ 0

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
8 0

Answer

x \geq -\frac{1}{2}

Step-by-step explanation:

I'm learning this to but I hope this helps :)

melisa1 [442]3 years ago
4 0

Answer:

2x+1

Step-by-step explanation:

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12.12.12.12 +7(3.3.3.3+3)<br> What the answer
Black_prince [1.1K]

Answer:

23.253528

Your welcome

4 0
3 years ago
The heights of twelve month old boys are normally distributed with a mean of 29.8 inches and a standard deviation of 1.2 inches.
Triss [41]

Answer:

About twenty-one percent of twelve month old boys are shorter than 28.8 inches.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.8, \sigma = 1.2

About twenty-one percent of twelve month old boys are shorter than what height?

This is the value of X when Z has a pvalue of 0.21. So it is X when Z = -0.805.

Z = \frac{X - \mu}{\sigma}

-0.805 = \frac{X - 29.8}{1.2}

X - 29.8 = -0.805*1.2

X = 28.8

About twenty-one percent of twelve month old boys are shorter than 28.8 inches.

4 0
4 years ago
A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the
Stells [14]

Answer:

\frac{5}{3} in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box=L\times B\times H

Substitute the values then we get

Volume of box=V(x)=(8-2x)(15-2x)x=(15x-2x^2)(8-2x)

V(x)=120x-30x^2-16x^2+4x^3

V(x)=4x^3-46x^2+120x

Differentiate w.r.t x

V'(x)=12x^2-92x+120

V'(x)=0

12x^2-92x+120=0

3x^2-23x+30=0

3x^2-18x-5x+30=0

3x(x-6)-5(x-6)=0

(x-6)(3x-5)=0

x-6=0\implies x=6

3x-5=0\implies x=\frac{5}{3}

Again differentiate w.r.t x

V''(x)=24x-92

Substitute x=6

V''(6)=24(6)-92=52>0

Substitute x=5/3

V''(5/3)=24(5/3)-92=-52

Hence, the volume is maximum at x=\frac{5}{3}

Therefore, the side of the square ,x=\frac{5}{3} in cutout that gives the box the largest possible volume.

5 0
3 years ago
I need help... like now.. please?
Shtirlitz [24]

Answer:

7 9/10 pounds

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can someone help me solve this? x/3+1/2=5/4
horsena [70]

Answer:

X= 9/4

Step-by-step explanation: multiply both sides by 12 and get 4x+6=15

Subtract 6 and get 4x=9

Divide 4 by both sides and get 9/4

9/4 is the answer

4 0
4 years ago
Read 2 more answers
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