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Annette [7]
3 years ago
13

HEY CAN ANYONE PLS ANSWER DIS!!!!!!!!

Physics
1 answer:
horsena [70]3 years ago
5 0

Answer:

1. synthesis 2. combustion

Explanation:

This is my guess

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A car has a mass of 2,500 kg. The car is accelerating at 0.5 m/s2. What is the net force acting on the car?
tekilochka [14]

Answer:

force:mass*acceleration

2500kg*0.5m/s2

1250N

6 0
3 years ago
Tranh slowed his skateboard as he
ICE Princess25 [194]

Answer:

Explanation:

Given parameters:

Initial velocity  = 8m/s

Final velocity  = 2m/s

Time taken  = 3seconds

Unknown and solution:

1. Is he accelerating or decelerating?

Tranh is obviously decelerating in this period. This is negative form of acceleration in which the speed reduces as the body comes to a stop.

Deceleration is a negative change in velocity with time i.e a body is reducing its velocity as time is changing.

2. What is the value?

 Mathematically;

          Deceleration  = \frac{Final velocity  - initial velocity}{time taken}

         Deceleration  = \frac{2 -8}{3}

                                  = -2m/s²

3 0
3 years ago
How to do this, i'm completely lost
vaieri [72.5K]
There are two torques t1 and t2 on the beam due to the weights, one torque t3 due to the weight of the beam, and one torque t4 due to the string.

You need to figure out t4 to know the tension in the string.

Since the whole thing is not moving t1 + t2 + t3 = t4.

torque t = r * F * sinФ = distance from axis of rotation * force * sin (∡ between r and F)

t1 =3.2 * 44g 
t2 = 7 * 49g 
t3 = 3.5 * 24g 

t4 = t1 + t2 + t3 = 5570,118

The t4 also is given by:

t4 = r * T * sin Ф

r = 7
Ф = 32°
T: tension in the string

T = t4 / (r * sinФ)

T = t4 / (7 * sin(32°)) 

T = 1501,6 N

8 0
4 years ago
Sound travels at a speed of about 344 m/s in air. You see a distant flash of lighting and hear the thunder arrive 7.6 seconds la
Mazyrski [523]

Answer:

0.056 miles away

Explanation:

From sound wave,

v = 2x/t .................................. Equation 1

Where v = velocity of sound in air, x = distance of echo, t = time.

making x the subject of the equation,

x = 2v/t........................... Equation 2.

Given: v = 344 m/s, t = 7.6 s.

Substituting into equation 2

x = 2(344)/7.6

x = 90.53 m.

x = 90.53/1609.344

x = 0.056 mile.

Thus the lighting strike 0.056 miles away

8 0
3 years ago
Find the magnitude of the net electric force exerted on this charge. Express your answer in terms of some or all of the variable
Yuri [45]

Answer:

Th steps is as shown in the attachment

Explanation:

from the diagram, its indicates that twelve identical charges are distributed evenly on the circumference of the circle. assuming one of gthe charge is shifted to the centre of he circle alomng the x axis, as such the charge is unbalanced and there is need ot balanced all the identical charges for the net force to be equal to zero.

The mathematical interpretation is as shown in the attachment.

3 0
3 years ago
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