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3 years ago

Tranh slowed his skateboard as he

Physics

1 answer:

ICE Princess25 [194]3 years ago

3 0

Answer:

Explanation:

Given parameters:

Initial velocity = 8m/s

Final velocity = 2m/s

Time taken = 3seconds

Unknown and solution:

1. Is he accelerating or decelerating?

Tranh is obviously decelerating in this period. This is negative form of acceleration in which the speed reduces as the body comes to a stop.

Deceleration is a negative change in velocity with time i.e a body is reducing its velocity as time is changing.

2. What is the value?

Mathematically;

Deceleration = $\frac{Final velocity - initial velocity}{time taken}$

Deceleration = $\frac{2 -8}{3}$

= -2m/s²

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A positively charged plastic ruler is brought close to a piece paper resting on the desk. The piece of paper was initially neutr

stealth61 [152]

Answer: static electricity

Explanation:

When the plastic ruler is rubbed, friction opposes the motion and causes the transfer of electron from one surface to another such that plastic becomes negatively charged. When ruler is brought nearer to the paper, it induces the positive charge in the piece of paper.

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3 years ago

A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 35.0 min

Lubov Fominskaja [6]

Explanation:

Solution:

Let the time be

t1=35min = 0.58min

t2=10min=0.166min

t3=45min= 0.75min

t4=35min= 0.58min

let the velocities be

v1=100km/h

v2=55km/h

v3=35km/h

a. Determine the average speed for the trip. km/h

first we have to solve for the distance

S=s1+s2+s3

S= v1t1+v2t2+v3t3

S= 100*0.58+55*0.166+35*0.75

S=58+9.13+26.25

S=93.38km

V=S/t1+t2+t3+t4

V=93.38/0.58+0.166+0.75+0.58

V=93.38/2.076

V=44.98km/h

b. the distance is 93.38km

6 0

3 years ago

2. Can you place three forces of 5g, 6g, and 12g so they are in equilibrium. Justify your answer.

Bond [772]

Answer:

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

Explanation:

Equilibrium means their sum must be zero.

Here the forces are 5g, 6g, and 12g.

For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

Here

Magnitude of largest force = 12 g

Sum of magnitudes of other forces = 5g + 6g = 11g

Magnitude of largest force > Sum of magnitudes of other forces

So this forces cannot form equilibrium.

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

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3 years ago

If the mass of both weights is 225 gm, the first mass is located 20∘ north of east, the second mass is located 20∘ south of east

Montano1993 [528]

Answer:

The voltage is 2.114 V.

Explanation:

Given that,

Mass of both weights = 225 gm

Transducer sensitivity = 0.5 V/N

The first mass is located 20∘ north of east, the second mass is located 20∘ south of east,

We need to calculate the net equivalent force

Using formula of force

$F_{3}=m_{1}g\cos\theta+m_{2}g\cos\theta$

$F_{3}=2mg\cos\theta$

Put the value into the formula

$F_{3}=2\times0.225\times10\cos20^{\circ}$

$F_{3}=4.228\ N$

We need to calculate the voltage

Using formula of voltage

$Voltage =sensitivity\times F_{3}$

Put the value into the formula

$Voltage=0.5\times4.228$

$Voltage =2.114\ V$

Hence, The voltage is 2.114 V.

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3 years ago

Which diagram represents an open circuit?

Kruka [31]

Answer : D) Circuit A

This circuit is the only circuit where it is not complete, having and open spot towards the bottom of it, making it and open circuit.

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