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2 years ago

CAN someone PLZ help!?!?

Mathematics

1 answer:

xxTIMURxx [149]2 years ago

5 0

Answer:

Step-by-step explanation:

First one is 0.066 cents and the second is is 15.266 dollars

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3 years ago

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A(c−b)=d solve for c

Rainbow [258]

Answer:

The solution to this equation could not be determined.

Step-by-step explanation:

Simplifying

a(c + -1b) = d

Reorder the terms:

a(-1b + c) = d

(-1b * a + c * a) = d

(-1ab + ac) = d

Solving

-1ab + ac = d

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Combine like terms: d + -1d = 0

-1ab + ac + -1d = 0

The solution to this equation could not be determined.

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2 years ago

Please answer questions 3 and 4 :))

Gnoma [55]

1.) D
2.) A................

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2 years ago

If M is the set of all square of integers that are less than 100 and N is the set of all positive odd numbers that are under 15,

ollegr [7]

A set is simply the group of numbers.

The set of M and N are: $M = \{1,4,9,16,25,36,49,64,81\}$ and $N= \{1,3,5,7,9,11,13\}$ .
The set of M n N is: $M\ n\ N = \{1,9\}$ .
The set of M u N is: $M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$

(a) The set of M and N

Given that:

M = squares of integers less than 100

N = Positive odd numbers less than 15

So, we have:

$M = \{1,4,9,16,25,36,49,64,81\}$

$N= \{1,3,5,7,9,11,13\}$

(b) M n N and M u N

M n N is the set of common elements between sets M and N.

So, we have:

$M\ n\ N = \{1,9\}$

M u N is the set of all elements in sets M and N.

So, we have:

$M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}$