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Zolol [24]
2 years ago
14

Which equation is represented by the graph below? HELP PLEASE

Mathematics
1 answer:
bonufazy [111]2 years ago
7 0

Answer: The answer is b

Step-by-step explanation:

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Need help, it’s an assignment ‍♀️
iris [78.8K]

1. copying

3. arc

4. ridgid motion

5. Distance Formula

6. image

7. transformation

8. translation

I don't really know if these are correct because I have never had to define any of those words or know a lot of these. But some of them I am pretty sure are right. I hope I helped some. I am sorry if I didn't. But this is my best guess.

7 0
3 years ago
the table below shows the function of f determine the value of f(3) that will lead to an average rate of change of 19 over the i
3241004551 [841]

ANSWER

f(3) =  - 25

EXPLANATION

We want to determine the value of f(3) that will lead to an average rate of change of 19 over the interval [3, 5].

The average rate of change of f(x) over the interval [a,b]:

=  \frac{f(b) - f(a)}{b - a}

If the average rate of change over the interval [3, 5] is 19, then;

\frac{f(5) - f(3)}{5 - 3}  = 19

From the to table f(5)=13

\frac{13 - f(3)}{2}  = 19

13 - f(3) = 19 \times 2

13 - f(3) = 38

- f(3) = 38 - 13

- f(3) = 25

f(3) =  - 25

7 0
2 years ago
A triangle with sides of lengths 9, 22, and 24 is a right triangle
Leona [35]

Answer:

The statement is false

Step-by-step explanation:

we know that

if the triangle is a right triangle

then

the triangle must satisfy the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

we have

c=24\ units

a=9\ units

b=22\ units

substitute

24^{2}=9^{2}+22^{2}

576=81+484

576 \neq 565

therefore

Is not a right triangle

The statement is false

4 0
2 years ago
What is the area of the trapezoid shown? trapezoid A = ______ units²?
notka56 [123]

Answer:

74.1 units²

Step-by-step explanation:

Area of the trapezoid shown = ½×(AD + BC)×BE

Use distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to find AD, BC, and BE.

✍️Distance between A(-9, 4) and D(9, 1):

AD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(9 -(-9))^2 + (1 - 4)^2}

= \sqrt{(18)^2 + (-3)^2}

= \sqrt{(324 + 9} = \sqrt{333}

AD = 18.2 units (nearest tenth)

✍️Distance between B(-4, -3) and C(2, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(2 -(-4))^2 + (-4 -(-3))^2}

= \sqrt{(6)^2 + (-1)^2}

= \sqrt{(36 + 1} = \sqrt{37}

BC = 6.1 units (nearest tenth)

✍️Distance between B(-4, -3) and E(-3, 3):

BE = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(-3 -(-4))^2 + (3 -(-3))^2}

= \sqrt{(1)^2 + (6)^2}

= \sqrt{(1 + 36} = \sqrt{37}

BE = 6.1 units (nearest tenth)

✔️Area of the trapezoid:

Area = ½×(AD + BC)×BE

Plug in the values into the formula

Area = ½×(18.2 + 6.1)×6.1

Area = ½×(24.3)×6.1

Area = 74.115 ≈ 74.1 units² (nearest tenth)

5 0
2 years ago
A motorcycle travels 325 miles at a speed of 50 mph. How much time did it take?
Blizzard [7]

Answer:

6 hrs and 30 minutes

Step-by-step explanation:

Because math:

325/50=6.5

4 0
3 years ago
Read 2 more answers
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