Answer:
<u>Student tickets are $14 each</u>
<u>Senior Citizen tickets are $4 each</u>
Step-by-step explanation:
Let C be the price of a Senior Citizen ticket, and S be the price of a Student ticket.
We learn that on the first day:
2C + 7S = $106
On the second day:
3C + 14S = $208
We have two equations and two unknowns. Rearrange either equation to isolate either C or S and use that value in the other equation.
I'll choose 2C + 7S = $106
C = ($106 - 7S)/2
Use this in the other equation:
3C + 14S = $208
3(($106 - 7S)/2) + 14S = $208
($318 - 21S)/2 + 14S = $208
$159 - 10.5S + 14S = $208
3.5S = $49
<u>S = $14 Student tickets are $14 each</u>
Use this answer in either equation to find C:
C = ($106 - 7S)/2
C = ($106 - 7($14))/2
C = $4 Senior Citizen tickets are $4 each
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Check to see if these values work in the original equations:
1. 2C + 7S = $106
2($4) + 7($14) = $106 ?
$8 + $98 = $106 ? <u>YES</u>
2. 3C + 14S = $208
3($4) + 14($14) = $208 ?
$12 + $196 = $208 ? <u> YES</u>
