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What is the apparent solution to the system of equations?

Leto [7]

Step-by-step explanation:

The given equations are :

y=-x+2 ....(1)

y = -4x +7 ....(2)

From equation (1) and (2)

-x+2 = -4x +7

Taking like terms together

-x+4x=7-2

3x = 5

x = 1.667

Put the value of x in equation (1)

y=-(1.667)+2

y = 0.333

The solution of the equations are (1.667,0.333). The attached figure shows the graph for the equations.

8 0

3 years ago

A mountain climber is at a height of 750 meters and begins his descent.

Lemur [1.5K]

Answer:

f(x)=750-15t

Step-by-step explanation:

He starts off at 750 meters, and he decends 15 meters psr minute

7 0

3 years ago

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Find the slope of the line on the graph

Oksana_A [137]

The slope is 3/1, which can be simplified to 3. Find it by traveling up 3 points and over 1 point form one intersection point to the next.

5 0

3 years ago

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Find the range of F<img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cfrac%7B2%7D%7Bx-7%7D%20" id="TexFormula1" title="f(x)= \fr

steposvetlana [31]

Answer: $y \in R; y \neq 0$
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.

Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.

Now, since we know the end behaviours, let's find the asymptotic behaviours.

As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.

So, our range would be: $y \in R; y \neq 0$

6 0

3 years ago

Melinda donated fudge for the school bake sale. She wrapped 80 pieces of fudge. Each piece of fudge weighed 1 ounce. How many po

xxMikexx [17]

Answer:

Melissa wrapped 5 pounds of fudge

Step-by-step explanation:

This is the correct question

Melinda donated fudge for the school bake sale. she wrapped 80 pieces of fudge. each piece of fudge weighed 1 ounce. how many pounds of fudge did melinda wrap?

In this question, we are asked to calculate the pounds of fudge wrapped by Melinda.

Firstly, we need to calculate the total weight of the fudge wrapped by Melinda in pounds.

From the question , we can identify that she wrapped 80 fudge with each of the fudge weighing 1 ounce each.

The total weight of all the fudge wrapped in ounces would be 80 * 1 = 80 ounces

Now, let’s convert this weight in ounces to pounds.

Mathematically, there are 16 ounces in a pound.

Hence, the weight in pounds of 80 ounces would be; 80/16 = 5 pounds

6 0

4 years ago

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