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DIA [1.3K]
3 years ago
11

If we go on the top of the Mountain we will our weight increase or decrease?​

Physics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

our weight would decrease.

Explanation:

because of you burning all those calories and fat from hiking up the mountain.

erma4kov [3.2K]3 years ago
7 0

Answer:

increase

Explanation:

guesshejwoowsnnsnakalalapqjhdjd

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Calculate ine gravitational potential energy of the ball using pe=m×g×h.(use g=9.8 n/kg)
Neko [114]

Answer:

58.8J

Explanation:

Given parameters;

Mass of ball  = 4kg

Height above the floor  = 1.5m

g  = 9.8n/kg

Unknown:

Potential energy  = ?

Solution:

The potential energy of a body is the energy due to the position of the body.

It is mathematically expressed as:

  Potential energy = mass x acceleration due to gravity x height

  Potential energy  = 4 x 9.8 x 1.5  = 58.8J

5 0
3 years ago
Which of the following would effect the speed of a wave ? A) the matter it travels through
Artemon [7]

Answer:

Option D

The frequency

Explanation:

The speed of wave is depedant only on the wavelength and frequency of waves since it is given by s=fw where s is the speed, f is frequency and w is the wavelength. Since the options given has only one factor, that is frequency, hence option D is correct. In case we had wavelength could be among the options, both would be correct.

5 0
3 years ago
Please Help.............................
Natalka [10]
Neutrons don't have any charge
7 0
3 years ago
Read 2 more answers
We have a toy gun with a spring constant of 50 N/m. The spring is compressed by 0.2 m. If you neglect friction and the mass of t
Arisa [49]

Answer:

31.6\:\mathrm{m/s}

Explanation:

The elastic potential energy of a spring is given by Us=\frac{1}{2}kx^2, where k is the spring constant of the spring and x is displacement from point of equilibrium.

When released, this potential energy will be converted into kinetic energy. Kinetic energy is given by KE=\frac{1}{2}mv^2, where m is the mass of the object and v is the object's velocity.

Thus, we have:

Us=KE,\\\frac{1}{2}kx^2=\frac{1}{2}mv^2

Substituting given values, we get:

\frac{1}{2}\cdot 50\cdot 0.2^2=\frac{1}{2}\cdot 0.002\cdot v^2,\\v^2=\frac{50\cdot 0.2^2}{0.002},\\v^2=1000,\\v\approx \boxed{31.6\:\mathrm{m/s}}

4 0
3 years ago
what is the potential difference across the headlight bulbs when the starter motor is operated, requiring an additional 39 a fro
frosja888 [35]

The starter motor's potential difference across the headlight bulbs is 38.45V, requiring an additional 39 a from the battery. Voltage, also known as potential difference.

It is sometimes described as the amount of work needed to move a test charge between two sites, expressed as a unit of charge. Volt is the potential difference's SI unit (V). We only take into account the charge between the locations P and Q when current moves between them in an electric circuit. Electric potential difference between two sites is referred to as voltage, also known as electric pressure, electric tension, or (electric) potential difference. an electric field that is static.

Vh = I*Rn

Vh = 39/5.476*5.40v

Vh = 38.45v

Learn more about voltage here

brainly.com/question/13521443

#SPJ4

5 0
1 year ago
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