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3 years ago

What is the speed of a ball thrown from 1.2m above the ground if it travels 13.7m horizontally before hitting the ground

Physics

1 answer:

Fudgin [204]3 years ago

4 0

Answer:

Explanation:

The trick is to find the time.

If the ball did not travel horizontally at all and was just dropped, how long would it take to hit the ground?

Givens

vi = 0

d = 1.2 m

a = 9.8 m/s^2

Formula

d = vi * t + 1/2 * a ^ t^2

Solution

1.2 = 0*t + 1/2 9.8 * t^2

1.2 = 4.9 t^2

t^2 = 1.2 / 4.9

t^2 = 0.245

sqrt(t^2) = sqrt(.245)

t = 0.4949 seconds

Answer

You are not very clear about which answer you want. There are two of them. One is going horizontally and the other is vertically.

Vertical

vf^2 = vi^2 + 2*a*d

vi = 0

a = 9.8

t = 0.4949

vf^2 =0^2 + 2 * 9.8 * 1.2

vf^2 = 23.52

sqrt(vf^2) = sqrt(23.52)

vf = 4.85 m/s

Horizontal

This is likely what you are looking for.

There is 0 acceleration horizontally.

d = 13.5 m

t = 0.4949

s = ?

s = d/t

s = 13.5/0.4949

s = 27.28

Note

You should note a couple of things.

The horizontal and vertical speeds are not the same.
The time is used for both the horizontal and vertical speeds.
The horizontal and vertical distances are quite different.
Horizontal accelerations for these type of questions is generally 0.

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2 years ago

A concrete piling of 50 kg is suspended from a steel wire of diameter 1.0 mm and length 11.2 m. How much will the wire stretch?

pentagon [3]

Explanation:

It is given that,

Mass of concrete pilling, m = 50 kg

Diameter of wire, d = 1 mm

Radius of wire, r = 0.0005 m

Length of wire, L = 11.2

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The young modulus of a wire is given by :

$Y=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta L}{L}}$

$Y=\dfrac{F.L}{A\Delta L}$

$\Delta L=\dfrac{F.L}{A.Y}$

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3 years ago

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Answer:

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Explanation:

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On the other hand, space station refers to a spacecraft that can support a group of human for long time in the orbit. Another names for space stations are orbital space station and orbital station.

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3 years ago

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Answer:

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Explanation:

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