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3 years ago

The force it would take to accelerate a 700-kg car at a rate of 5 m/s2 is

Physics

1 answer:

aev [14]3 years ago

7 0

Answer:3500N

Explanation:

mass=700kg

acceleration=5m/s^2

Force=mass x acceleration

Force=700 x 5

Force=3500

Force=3500N

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The following acceleration vs time plots show

fenix001 [56]

The data set that is most likely from the car equipped with ABS is :

The First ( upper ) plot

Although the plots related to your question is missing attached below is the missing data.

The First plot ( acceleration vs time ) plot is the data that represents the application of brakes in a car fitted with ABS ( antilock braking system ) because of the absence of skidding effect between 6.5 and 9 seconds in the graph.

The skidding effect is present in the second plot around the same time because the car is not fitted with ABS

Hence we can conclude that the graph that shows the car fitted with ABS is the first plot .

Learn more : brainly.com/question/4360615

7 0

3 years ago

Transverse thrusters are used to make large ships fully maneuverable at low speeds without tugboat assistance. A transverse thru

suter [353]

Answer:

Thrust developed = 212.3373 kN

Explanation:

Assuming the ship is stationary

Determine the Thrust developed

power supplied to the propeller ( Punit ) = 1900 KW

Duct distance ( diameter ; D ) = 2.6 m

first step : calculate the area of the duct

A = π/4 * D^2

= π/4 * ( 2.6)^2 = 5.3092 m^2

next : calculate the velocity of propeller

Punit = (A*v*β ) / 2 * V^2 ( assuming β = 999 kg/m^3 ) also given V1 = 0

∴V^3 = Punit * 2 / A*β

= ( 1900 * 10^3 * 2 ) / ( 5.3092 * 999 )

hence V2 = 8.9480 m/s

Finally determine the thrust developed

F = Punit / V2

= (1900 * 10^3) / ( 8.9480)

= 212.3373 kN

8 0

3 years ago

A stunt driver rounds a banked, circular curve. The driver rounds the curve at a high, constant speed, such that the car is just

Sladkaya [172]

Answer:

option C and D

Explanation:

When a stunt driver is rotating on the banked road the force which is responsible for the centripetal acceleration of the car is Frictional force and the Normal Force.

The Frictional force component of the banked road will protect the car from skidding.

And the normal force component will protect the car from toppling inward due to centripetal force acting on it.

Hence, the correct answer is option C and D

7 0

3 years ago

A steel rod is pulled in tension along its center axis (the axial direction) with a stress that is less than the yield strength.

Kamila [148]

Answer:

D. Axial stress divided by axial strain

Explanation:

Lets take rod is pulled by force P

Stress σ = P/A

We know that

σ = ε E

E= Lets take rod is pulled by force P

Stress σ = P/A

We know that

σ = ε E

σ=Axial stress

ε =Axial Strain = ΔL/L

E= σ/ε

E= Axial stress/Axial Strain

So the modulus of elasticity is the ratio of axial stress to axial strain.

σ=Axial stress

ε =Axial Strain = ΔL/L

E= σ/ε

E= Axial stress/Axial Strain

So the modulus of elasticity is the ratio of axial stress to axial strain.

The option D is correct.

6 0

3 years ago

Assume that an intercontinental ballistic missile goes from rest to a suborbital speed of 6.50 km/s in 60.0 s (the actual speed

olasank [31]

Answer:

Average acceleration is $(11.05)g\ m/s^2$

Explanation:

It is given that,

Initial velocity, u = 0

Final velocity, v = 6.5 km/s = 6500 m/s

Time taken, t = 60 s

Acceleration, $a=\dfrac{v-u}{t}$

$a=\dfrac{v}{t}$

$a=\dfrac{6500\ m/s}{60}$

$a=108.33\ m/s^2$

Since, $g=9.8\ m/s^2$

So, $a=(11.05)g\ m/s^2$

So, the angular acceleration of the missile is $(11.05)g\ m/s^2$ . Hence, this is the required solution.

4 0

3 years ago