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PtichkaEL [24]
3 years ago
13

Is it just me? or does tutoring never work anymore :/ ​

Mathematics
1 answer:
Ghella [55]3 years ago
6 0

Answer:

Its not you, that's for sure.

You might be interested in
Find a fraction with a demominator of 30 that is equivalent to 1/3
Harman [31]

Answer:

10/30

Step-by-step explanation:

First, multiply the denominator by 10 to make 30.

Then, since we multiplied the denominator, we multiply the numerator. 1 x 10= 10

Therefore the answer is 10/30.

4 0
3 years ago
Factor the following polynomial.<br> 98x3 – 18x
grigory [225]

Answer:

2x(7x - 3)(7x +3)

Step-by-step explanation:

Find common factors between the 2 numbers:

98x^3 - 18x

2x(49x^2 - 9)

now find what numbers multiplied together is 49, and find what numbers added together equals 0 and the product is 3, 7 times 7 is 49 and 3(-3) = 9 while 3 - 3 = 0 so:

2x(7x - 3)(7x +3)

3 0
3 years ago
Read 2 more answers
mix 2parts red with 3parts cream and 1part blue how much cream and blue paint do i need to mix with 4litres of red
vagabundo [1.1K]
The 4 litres of red has to be 2 parts of the mixture, so each part will be 2 litres. Therefore 3 parts of cream will be 6 litres and the one part of blue will be 2 litres.
7 0
4 years ago
Read 2 more answers
Will Mark Brilliant!
pochemuha

Answer:

87.8

Step-by-step explanation:

I assume you know how to do this so I didn't show any steps. Have a nice night. :)

8 0
3 years ago
What is normal, when it comes to people's body temperature? a random sample of 130 human body temperatures, provided by allen sh
nikitadnepr [17]
The two-sided alternative hypothesis is appropriate in this case, the reason being we are asked "does the data indicate that the average body temperature for healthy humans is different from 98.6◦........?".
The test statistic is:
Z= \frac{\bar{X}-\mu}{ \frac{s}{ \sqrt{n} } }} =-5.47
Using an inverse normal table, and halving \alpha for a two-tailed test, we look up p=0.5-\alpha/2=0.5-0.005=0.495 and find the critical value to be Z = 2.5758.
Comparing the test statistic Z = -5.47 with the rejection region Z < -2.5758 and Z > 2.5758. we find the test statistic lies in the rejection region. Therefore the evidence does not indicate that the average body temperature for healthy humans is different from 98.6◦.
 
7 0
3 years ago
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