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3 years ago

Find the rest of the triangle.

Mathematics

2 answers:

tia_tia [17]3 years ago

4 0

Answer:B

Step-by-step explanation:

timurjin [86]3 years ago

3 0

The answer is b because m

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jasenka [17]

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Step-by-step explanation:

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3 years ago

9 + 4 to the third power x (20-8) / 2 + 6

harkovskaia [24]

1110.5 is the answer and your welcome

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2 years ago

he conditional relative frequency table was generated using data that compared the cost of one ticket for a performancehe method

ludmilkaskok [199]

The <u>correct answer</u> is:

0.14.

Explanation:

We are asked "Given that Lorenzo paid more than $30 for a ticket, what is the probability that he purchased the ticket at the box office?"

Using the conditional relative frequency table, we start at the column "More than $30". We then go to the row "Purchased at the Box Office." The value in this cell is 0.14; this is the probability.

7 0

3 years ago

Read 2 more answers

Given f(x) = 4(x - 8), determine the value of f(10).

Komok [63]

Answer:

f(x) = 4(x - 8)

4 (10 -8) = 8

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

5 0

3 years ago

Find the rest of the triangle.​

Find the rest of the triangle.