Answer and explanation;
-The insulin receptor itself has decreased kinase activity leading to fewer binding sites for singling effectors to become activated.
Therefore; the signaling effectors are less likely to be activated.
-Additionally,, feedback inhibition decreases signaling effector binding to receptor.
-The lack of activation of these initial signaling effectors prevents any subsequent steps from happening.
-We can thus conclude this by saying that higher insulin concentrations are necessary to obtain the same level of signaling leading to physiological effects that would exist in someone without type-2 diabetes.
-Also the requirement for higher insulin concentration means that the cells that respond to insulin are resistant to its effect.
Answer:
a. Only the DNA of β cells contains the gene for insulin; only the DNA of chief cells contains the gene for pepsinogen
Explanation:
As stated in the question above, insulin production is exclusive to β cells in the pancreas. This is because only these cells have a gene that manages the production and excretion of insulin within an organism. Similarly, only the main cells of the stomach have the capacity to produce pepsinogen, which indicates that the gene responsible for managing this production is unique to these cells.
Answer: 100% (4/4)
Explanation: Since the woman’s trait is dominant it will mask the normal stature in all their offspring. For example, A = achondroplasia trait, a = normal stature. It is very possible that the woman carries the trait and her offspring who may not possess it can pass it on to their offspring
Two traits that we are examining are the color (purple/white) and the smoothness.
In our sample, we have 135 individuals ( 75 +28+24+8= 135).
Since we know that expected ratio of a dihybrid cross, is <span>9:3:3:1 we can calculate what is the expected values of each phenotype is.
So, for the white wrinkled phenotype, we expect that there will be one-sixteenth of the whole sample ( there are 16 parts of the whole sample 9+3+3+1=16).
So, we multiply the whole sample- 135 with one-sixteenth (or </span>0.0625) and get 8,4375.
When you calculate the values for all phenotypes you get results shown in the attached excel table.
When you have your expected and experimental values you compare them with a chi-square test. (The test determines if the difference between the expected and experimental results is statistically significant).