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3 years ago

Can you please answer my question correctly ASAP

Physics

1 answer:

lana66690 [7]3 years ago

5 0

Answer:

1) C, 2) C, 3) B, 4) D, 5) A/B, 6) D, 7) D, 8) A, 9) B, 10) A

Explanation:

1) Seconds, minutes and days are time units. (Correct answer: C)

2) The displacement is shortest distance between the point of origin and the point of destination. (Correct answer: C)

3) The velocity is the rate of change of position in time. (Correct answer: B)

4) Graphs are a very useful ressource to infer characteristics inherent to a studied physical variable. (Correct answer: D)

5) There are two possible answers, since both milimeters and meters are units for distance. (Correct answers: A/B)

6) The distance is the arc length of the entire path that object travelled. (Answer: D)

7) Traditionally, in a position vs. time graph we plot time in the x-axis. (Answer: D)

8) In this case, we use a distance-time graph, where travelled distance is the dependent variable and time is the independent variable. (Answer: A)

9) The point of origin is the initial position of the object. (Answer: B)

10) The point of destination is the final position of the object. (Answer: A)

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Most of the really bright stars in our sky are NOT among the stars that are very close to us. Why then do they look so bright to

Yanka [14]

Answer:

stars will emit more light due to their Luminosity, so they look very bright.

Explanation:

Luminous refers to..,

The total amount of energy radiated by a star or other celestial object per second.
Therefore it is the power output of a star.

Most of the really bright stars in our sky are not that very close to us yet they look bright because of the Luminosity of the star.

These stars are intrinsically so luminous.

A star's power output across all wavelengths is called its bolometric luminosity.

A star with large luminosity will have more measure of radiated electromagnetic power meaning.

so it will emit more light than a low luminosity star.

Hence,

those stars can easily be seen even across great distance.

learn more about Luminosity of the star here:

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6 0

2 years ago

Two point charges are separated by 10 cm, with an attractive force between them of 15 N. Find the force between them when they a

suter [353]

Answer:

(a) the force is 8.876 N

(b) the magnitude of each charge is 4.085 μC

Explanation:

Part (a)

Given;

coulomb's constant, K = 8.99 x 10⁹ N.m²/C²

distance between two charges, r = 10 cm = 0.1 m

force between the two charges, F = 15 N

when the distance between the charges changes to 13 cm (0.13 m)

force between the two charges, F = ?

Apply Coulomb's law;

$F = \frac{Kq_1q_2}{r^2} \\\\let \ Kq_1q_2 = C\\\\F =\frac{C}{r^2} \\\\C = Fr^2\\\\F_1r_1^2 = F_2r_2^2\\\\F_2 =\frac{F_1r_1^2}{r_2^2} \\\\F_2 = \frac{15*0.1^2}{0.13^2} \\\\F_2 = 8.876 \ N$

Part (b)

the magnitude of each charge, if they have equal magnitude

$F = \frac{KQ^2}{r^2}$

where;

F is the force between the charges

K is Coulomb's constant

Q is the charge

r is the distance between the charges

$F = \frac{KQ^2}{r^2} \\\\Q = \sqrt{\frac{Fr^2}{K} } \\\\Q = \sqrt{\frac{15*(0.1)^2}{8.99*10^9} } = 4.085 *10^{-6} \ C\\\\Q = 4.085 \ \mu C$

4 0

3 years ago

How are longitudinal and transverse waves different?

Natalija [7]

Answer:

A longitudinal wave is a wave where the movement of the medium is in the same direction as the wave. On the other hand, a transverse wave is a wave where the movement of the medium is at a right angle to the wave direction.

Explanation:i got this right on a quiz so i know its right

3 0

3 years ago

Answer the question based on this waveform.

Nuetrik [128]

Answer:

Cannot be determined from the given information

Explanation:

Given the following data;

Velocity = 24 m/s

Period = 3 seconds

To find the amplitude of the wave;

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

x is displacement of the wave measured in meters.

A is the amplitude.

ω is the angular frequency measured in rad/s.

t is the time period measured in seconds.

ϕ is the phase angle.

Hence, the information provided in this exercise isn't sufficient to find the amplitude of the waveform.

However, the given parameters can be used to calculate the frequency and wavelength of the wave.

6 0

3 years ago

What is the Coriolis Effect?

Crazy boy [7]

Answer:

An effect whereby a mass moving in a rotating system experienced a force acting perpendicular to the direction of motion and to the axis of rotation.

3 0

3 years ago

Can you please answer my question correctly ASAP​

Can you please answer my question correctly ASAP