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3 years ago

Can you please answer my question correctly ASAP

Physics

1 answer:

lana66690 [7]3 years ago

5 0

Answer:

1) C, 2) C, 3) B, 4) D, 5) A/B, 6) D, 7) D, 8) A, 9) B, 10) A

Explanation:

1) Seconds, minutes and days are time units. (Correct answer: C)

2) The displacement is shortest distance between the point of origin and the point of destination. (Correct answer: C)

3) The velocity is the rate of change of position in time. (Correct answer: B)

4) Graphs are a very useful ressource to infer characteristics inherent to a studied physical variable. (Correct answer: D)

5) There are two possible answers, since both milimeters and meters are units for distance. (Correct answers: A/B)

6) The distance is the arc length of the entire path that object travelled. (Answer: D)

7) Traditionally, in a position vs. time graph we plot time in the x-axis. (Answer: D)

8) In this case, we use a distance-time graph, where travelled distance is the dependent variable and time is the independent variable. (Answer: A)

9) The point of origin is the initial position of the object. (Answer: B)

10) The point of destination is the final position of the object. (Answer: A)

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making sure that you change one factor at a time while keeping all other conditions the same

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An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How

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Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

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u is the initial velocity

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For this problem,

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and

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So, substituting t = 1 s, we find

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4 years ago

suppose an electrically charged ruler transfers some of its charge by contact to a tiny plastic sphere. will the ruler and the s

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Answer:

Here ball and rod will repel each other as they are of similar charges

Explanation:

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$F = \frac{kq_1q_2}{r^2}$

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3 years ago

Object height 10cm is placed in front of plane mirror.The height of the image will be_______?

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3 years ago

A disk with radius R and uniform positive charge density s lies horizontally on a tabletop. A small plastic sphere with mass M a

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Answer:

a. F = Qs/2ε₀[1 - z/√(z² + R²)] b. h = (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

Explanation:

a. What is the magnitude of the net upward force on the sphere as a function of the height z above the disk?

The electric field due to a charged disk with surface charge density s and radius R at a distance z above the center of the disk is given by

E = s/2ε₀[1 - z/√(z² + R²)]

So, the net force on the small plastic sphere of mass M and charge Q is

F = QE

F = Qs/2ε₀[1 - z/√(z² + R²)]

b. At what height h does the sphere hover?

The sphere hovers at height z = h when the electric force equals the weight of the sphere.

So, F = mg

Qs/2ε₀[1 - z/√(z² + R²)] = mg

when z = h, we have

Qs/2ε₀[1 - h/√(h² + R²)] = mg

[1 - h/√(h² + R²)] = 2mgε₀/Qs

h/√(h² + R²) = 1 - 2mgε₀/Qs

squaring both sides, we have

[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²

h²/(h² + R²) = (1 - 2mgε₀/Qs)²

cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² = (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² = √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h = (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

4 0

3 years ago

Can you please answer my question correctly ASAP​

Can you please answer my question correctly ASAP